Python之雙色球選購和三級菜單問題

1：雙色球選購
# 1 雙色球（假設一共八個球，6個紅球，球號1-32、2個藍球，球號1-16）
# 2 確保用戶不能重復選擇，不能超出范圍
# 3 用戶輸入有誤時有相應的錯誤提示
# 4 最后展示用戶選擇的雙色球的號碼

select_red_ball = []
while True:
    n = int(input('請輸入你要選擇的紅色球(1-32)：'))
    if 0 < n < 33:
        if n not in select_red_ball:
            select_red_ball.append(n)
        else:
            print('number %d is already exist in red ball list' % n)
    else:
        print('only can select n between 1-32')
    if len(select_red_ball) == 6:
        break
select_red_ball.sort()
select_blue_ball = []
while True:
    n = int(input('請輸入你要選擇的藍色球(1-32)：'))
    if 0 < n < 17:
        if n not in select_blue_ball:
            select_blue_ball.append(n)
        else:
            print('number %d is already exist in blue ball list' % n)
    else:
        print('only can select n between 1-16')
    if len(select_blue_ball) == 2:
        break
select_blue_ball.sort()
print('red ball %d' % select_red_ball)
print('blue ball %d' % select_blue_ball)

 

 

2 ：三級菜單

• 數據結構：
  menu = {
      '北京':{
          '海淀':{
              '五道口':{
                  'soho':{},
                  '網易':{},
                  'google':{}
              },
              '中關村':{
                  '愛奇藝':{},
                  '汽車之家':{},
                  'youku':{},
              },
              '上地':{
                  '百度':{},
              },
          },
          '昌平':{
              '沙河':{
                  '老男孩':{},
                  '北航':{},
              },
              '天通苑':{},
              '回龍觀':{},
          },
          '朝陽':{},
          '東城':{},
      },
      '上海':{
          '閔行':{
              "人民廣場":{
                  '炸雞店':{}
              }
          },
          '閘北':{
              '火車站':{
                  '攜程':{}
              }
          },
          '浦東':{},
      },
      '山東':{},
  }
  
  需求：
  可依次選擇進入各子菜單
  可從任意一層往回退到上一層
  可從任意一層退出程序
  所需新知識點：列表、字典

代碼一：

 exit_flag = False
while not exit_flag:
    for i in menu:
        print(i)
    choice1 = input("選擇進入1>>:")
    if choice1 in menu:
        while not exit_flag:
            for i2 in menu[choice1]:
                print("\t", i2)
            choice2 = input("選擇進入2>>:")
            if choice2 in menu[choice1]:
                while not exit_flag:
                    for i3 in menu[choice1][choice2]:
                        print("\t\t", i3)
                    choice3 = input("選擇進入3>>:")
                    if choice3 in menu[choice1][choice2]:
                        for i4 in menu[choice1][choice2][choice3]:
                            print("\t\t", i4)
                        choice4 = input("最后一層，按b返回>>:")
                        if choice4 == "b":
                            pass
                        elif choice4 == "q":
                            exit_flag = True
                    if choice3 == "b":
                        break
                    elif choice3 == "q":
                        exit_flag = True
            if choice2 == "b":
                break
            elif choice2 == "q":
                exit_flag = True

代碼二：（優化版本，代碼縮減為15行）

current_layer = menu
parent_layer = []  # 將父級key值放入到列表中
flags = False  # 設置標志位
while not flags:
    for key in current_layer:
        print(key)
    choose = input("請選擇，輸入b返回上一級菜單，輸入q退出菜單:").strip()  # 去除空格
    if choose in current_layer:
        parent_layer.append(current_layer)  # 將當前的狀態放入列表中
        current_layer = current_layer[choose]
    elif choose == 'b':
        if parent_layer:
            current_layer = parent_layer.pop()
    elif choose == 'q':
        flags = True
    else:
        print('輸入有誤，請重新輸入')