【Swagger2】【1】匹配多個controller

前言：項目中有多個模塊，所以有多個controller層。我是用方案二的

正文：

方案一：使用多個controller的共同擁有的父類

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.xx"))
            .paths(PathSelectors.any())
            .build();
}

方法二：指定所有controller的都實現的一個接口，比如@RestController

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.withClassAnnotation(RestController.class))
            .paths(PathSelectors.any())
            .build();
}

錯誤的兩種寫法

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.xx.*.controller"))
            .paths(PathSelectors.any())
            .build();
}

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.xx.course.controller"))
            .apis(RequestHandlerSelectors.basePackage("com.xx.user.controller"))
            .paths(PathSelectors.any())
            .build();
}

參考博客：

swagger2 如何匹配多個controller - 賈樹丙 - 博客園
http://www.cnblogs.com/acm-bingzi/p/swagger2-controller.html