java多線程（6）模擬排隊叫號程序，4個線程都干活並且結果正確

package com.com.wangwenjun.concurrent.chapter04;

import java.util.Random;
import java.util.concurrent.TimeUnit;

/**
 * @description: for循環主要解決的是線程的生命周期完成后又進行一輪
 * @author: 
 * @create: 
 **/

public class TicketWindowRunnable implements Runnable{

    private  int index = 1;
    private boolean change = true;

    private final static int MAX = 50;

    private final static Object MUTEX = new Object();

    @Override
    public void run() {
        synchronized(MUTEX){
            while(index <= MAX && change ){
                System.out.println(Thread.currentThread().getName() + " 的號碼是： " +(index++));

                try {
//                    TimeUnit.MILLISECONDS.sleep(new Random().nextInt(1000));
                    TimeUnit.MILLISECONDS.sleep(10);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }

               change = false;
            }
            change = true;

        }
    }

    public static void main(String[] args){
        final TicketWindowRunnable task = new TicketWindowRunnable();

        //4為線程個數據，也就是要循環至少13次
        for(int i = 0; i < MAX/4 + 1; i++){

            Thread windowThread1 = new Thread(task, "一號窗口");
            Thread windowThread2 = new Thread(task, "二號窗口");
            Thread windowThread3 = new Thread(task, "三號窗口");
            Thread windowThread4 = new Thread(task, "四號窗口");

            windowThread1.start();
            windowThread2.start();
            windowThread3.start();
            windowThread4.start();

        }
        
    }
}