SQL SERVER-查詢爆破sa密碼的主機

drop table if exists #sql
create table #sql
(
Logdatae varchar(50),
processinfo varchar(50),
[text] varchar(max)

)
go

INSERT INTO  #sql
Exec xp_readerrorlog 0
Go

SELECT distinct right(text,16)FROM #sql  WHERE Logdatae like  'Apr 17 2019%'  
AND text LIKE 'Login failed for user ''sa''. Reason: Password did not match that for the login provided%'