簡單易懂解決漢諾塔問題


一、首先,漢諾塔問題說簡單不簡單,說容易不容易,所以就是難,,,,(孩子欠揍)

下面是我給大家提供的源代碼,僅供參考

import turtle class Stack: def __init__(self): self.items = [] def isEmpty(self): return len(self.items) == 0 def push(self, item): self.items.append(item) def pop(self): return self.items.pop() def peek(self): if not self.isEmpty(): return self.items[len(self.items) - 1] def size(self): return len(self.items) def drawpole_3():#畫出漢諾塔的poles t = turtle.Turtle() t.hideturtle() def drawpole_1(k): t.up() t.pensize(10) t.speed(100) t.goto(400*(k-1), 100) t.down() t.goto(400*(k-1), -100) t.goto(400*(k-1)-20, -100) t.goto(400*(k-1)+20, -100) drawpole_1(0)#畫出漢諾塔的poles[0] drawpole_1(1)#畫出漢諾塔的poles[1] drawpole_1(2)#畫出漢諾塔的poles[2] def creat_plates(n):#制造n個盤子 plates=[turtle.Turtle() for i in range(n)] for i in range(n): plates[i].up() plates[i].hideturtle() plates[i].shape("square") plates[i].shapesize(1,8-i) plates[i].goto(-400,-90+20*i) plates[i].showturtle() return plates def pole_stack():#制造poles的棧 poles=[Stack() for i in range(3)] return poles def moveDisk(plates,poles,fp,tp):#把poles[fp]頂端的盤子plates[mov]從poles[fp]移到poles[tp] mov=poles[fp].peek() plates[mov].goto((fp-1)*400,150) plates[mov].goto((tp-1)*400,150) l=poles[tp].size()#確定移動到底部的高度(恰好放在原來最上面的盤子上面) plates[mov].goto((tp-1)*400,-90+20*l) def moveTower(plates,poles,height,fromPole, toPole, withPole):#遞歸放盤子 if height >= 1: moveTower(plates,poles,height-1,fromPole,withPole,toPole) moveDisk(plates,poles,fromPole,toPole) poles[toPole].push(poles[fromPole].pop()) moveTower(plates,poles,height-1,withPole,toPole,fromPole) myscreen=turtle.Screen() drawpole_3() n=int(input("請輸入漢諾塔的層數並回車:\n")) plates=creat_plates(n) poles=pole_stack() for i in range(n): poles[0].push(i) moveTower(plates,poles,n,0,2,1) myscreen.exitonclick()

 

把代碼復制好,在python 3.7.2 Shell上運行,如圖

 

 

可以看到效果,如圖

 

 

 

 這樣漢諾塔問題就基本解決了,歡迎大家來評論-_- -_- -_-

 


免責聲明!

本站轉載的文章為個人學習借鑒使用,本站對版權不負任何法律責任。如果侵犯了您的隱私權益,請聯系本站郵箱yoyou2525@163.com刪除。



 
粵ICP備18138465號   © 2018-2025 CODEPRJ.COM