算法比較簡單,注釋就能說明問題,直接上代碼!
方法一:(利用遞歸實現)
public static String reverse1(String s) {
int length = s.length();
if (length <= 1)
return s;
String left = s.substring(0, length / 2);
String right = s.substring(length / 2, length);
return reverse1(right) + reverse1(left); //調用遞歸
}
方法二:(拼接字符串)
public static String reverse2(String s) {
int length = s.length();
String reverse = "";
for (int i = 0; i < length; i++)
reverse = s.charAt(i) + reverse;
return reverse;
}
方法三:(利用數組,倒序輸出)
public static String reverse3(String s) {
char[] array = s.toCharArray();
String reverse = "";
for (int i = array.length - 1; i >= 0; i--)
reverse += array[i];
return reverse;
}
方法四:(利用StringBuffer的內置reverse方法)
public static String reverse4(String s) {
return new StringBuffer(s).reverse().toString();
}
方法五:(利用臨時變量,交換兩頭數值)
public static String reverse5(String orig) {
char[] s = orig.toCharArray();
int n = s.length - 1;
int halfLength = n / 2;
for (int i = 0; i <= halfLength; i++) {
char temp = s[i];
s[i] = s[n - i];
s[n - i] = temp;
}
return new String(s);
}
方法六:(利用位異或操作,交換兩頭數據)具體交換原理,參考上一篇文章
public static String reverse6(String s) {
char[] str = s.toCharArray();
int begin = 0;
int end = s.length() - 1;
while (begin < end) {
str[begin] = (char) (str[begin] ^ str[end]);
str[end] = (char) (str[begin] ^ str[end]);
str[begin] = (char) (str[end] ^ str[begin]);
begin++;
end--;
}
return new String(str);
}
方法七:(利用棧結構)
public static String reverse7(String s) {
char[] str = s.toCharArray();
Stack<Character> stack = new Stack<Character>();
for (int i = 0; i < str.length; i++)
stack.push(str[i]);
String reversed = "";
for (int i = 0; i < str.length; i++)
reversed += stack.pop();
return reversed;
}
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作者:guomutian911
來源:CSDN
原文:https://blog.csdn.net/guomutian911/article/details/48912617
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