C# 獲取Newtonsoft.Json的JObject多層節點內容

json形如

{

  "object":{

  "name":"cwr"

  },

  "others":"123"

}

 

要獲取name的值，則需要構造兩個JObject來獲取，如下：

JObject json = JObject.Parse(jsonresult);

string name = ((JObject)json["object"])["name"].ToString();

 

json形如

{

  "object":{

  "name": [

       {

         "firstname" : "cwr",

         "lastname" : "cwr"

        }

      ]

  },

  "others":"123"

}

獲取firstname的值如下：

JObject json = JObject.Parse(jsonresult);

string firstname = ((JObject)((JObject)json["object"])["name"][0])[firstname].ToString();