前言
一個學生可以對應多個老師,一個老師也可以教多個學生,這就是一種多對多的關系
models建表
新建一個老師表Teacher,和一個學生表Student
class Teacher(models.Model):
'''老師表'''
teacher_name = models.CharField(max_length=30, verbose_name="老師", default="")
tel = models.CharField(max_length=30, verbose_name="電話", default="")
mail = models.CharField(max_length=30, verbose_name="郵箱", default="")
class Meta:
verbose_name = "老師"
verbose_name_plural = verbose_name
def __str__(self):
return self.teacher_name
class Student(models.Model):
'''學生表'''
student_id = models.CharField(max_length=30, verbose_name="學號", default="")
name = models.CharField(max_length=30, verbose_name="姓名", default="")
age = models.IntegerField(verbose_name="年齡", default="")
# 多對多
teachers = models.ManyToManyField(Teacher, verbose_name="老師")
class Meta:
verbose_name = "學生"
verbose_name_plural = verbose_name
def __str__(self):
return self.name
之后執行 makemigrations 和migrate,同步數據
python manage.py makemigrations
python manage.py migrate
同步之后數據庫里面會新增三張表:student、teacher、student_teachers
shell模式新增數據
為了調試方便,可以使用django的shell模式,對表的數據增刪改查操作,打開cmd,cd到manage.py目錄
python manage.py shell
多對多表的增加數據
>>> from hello.models import Teacher, Student
>>> t1=Teacher.objects.create(teacher_name='劉老師',tel='155300001111',mail='1000@qq.com')
>>> t1.save()
>>> t1
<Teacher: Teacher object (1)>
>>> t2=Teacher.objects.create(teacher_name='萬老師',tel='155300001112',mail='1001@qq.com')
>>> t2.save()
>>> t2
<Teacher: Teacher object (2)>
>>> s1=Student.objects.create(student_id='11002200',name='張三',age=19)
>>> s1.save()
# 方法一:添加id
# 可以添加Teacher對應的id
>>> s1.teachers.add(1)
# 也可以添加多個id,逗號隔開
>>> s1.teachers.add(1,2)
# 如果添加的是傳一個可迭代對象(list或tupule),可以用*分開傳入這種方法
>>> s1.teachers.add(*[1,2])
# 方法二、直接添加對象
>>> s1.teachers.add(t1)
>>> s1.teachers.add(t2)
>>> s1.teachers.add(t1,t2)
# 也可以先查詢需要添加的對象
>>> ob=Teacher.objects.get(teacher_name='劉老師')
>>> ob
<Teacher: Teacher object (1)>
>>> s2=Student.objects.create(student_id='11002201',name='李四',age=19)
>>> s2.teachers.add(ob)
正向查詢
通過student表對象,查詢到對應的teacher
>>> from hello.models import Teacher, Student
>>> stu=Student.objects.filter(name='李四').first()
>>> stu
<Student: Student object (2)>
>>> stu.student_id
'11002201'
# 正向查詢
>>> stu.teachers.all()
<QuerySet [<Teacher: Teacher object (1)>]>
>>> stu.teachers.all()[0].teacher_name
'劉老師'
>>> stu.teachers.all()[0].tel
'155300001111'
反向查詢_set
通過老師名稱,查詢對應關聯的學生,反向查詢的時候在關聯表名稱后面加_set,如果設置related_name參數,就用related_name參數對應名稱查詢
參考上一篇https://www.cnblogs.com/yoyoketang/p/10573218.html
>>> tea=Teacher.objects.filter(teacher_name='劉老師').first()
>>> tea
<Teacher: Teacher object (1)>
>>> tea.tel
'155300001111'
# 反向查詢
>>> tea.student_set.all()
<QuerySet [<Student: Student object (1)>, <Student: Student object (2)>]>
>>> tea.student_set.all()[0].name
'張三'
>>>
xadmin注冊表
# adminx.py
import xadmin
from .models import Card, CardDetail, Teacher, Student
class ControlTeacher(object):
# 顯示的字段
list_display = ["teacher_name", "tel", "mail"]
class ControlStudent(object):
# 顯示的字段
list_display = ('student_id', 'name', 'age', '老師')
# # 定義一個方法,遍歷book的auth,然后用列表返回
def 老師(self, obj):
return [x.teacher_name for x in obj.teachers.all()]
xadmin.site.register(Teacher, ControlTeacher)
xadmin.site.register(Student, ControlStudent)
xadmin后台顯示效果