1:這個例子用spirngboot整合mybatis,jdbc等技術開發的
2:步驟
2.1:新建一個工程


主要的兩個步驟已經貼圖了,第二張圖是直接在pom.xml文件中加入依賴
2.2:新建完項目,就創建一個數據表
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CREATE TABLE `tuser` (
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`id` int(11) NOT NULL AUTO_INCREMENT,
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`loginname` varchar(20) DEFAULT NULL,
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`password` varchar(20) DEFAULT NULL,
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PRIMARY KEY (`id`)
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) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8
創建一個名為tuser的數據表
2.3:把項目所需的包和文件夾補充完整

2.4整合jdbc,在application.yml中加入jdbc的支持
spring:
datasource:
url: jdbc:mysql://127.0.0.1:3306/springboot?useUnicode=true&characterEncoding=utf-8 driver-class-name: com.mysql.jdbc.Driver username: root password: 123456
2.5整合springmvc的前端控制器,在application.yml中加入
spring:
mvc:
view:
prefix: /WEB-INF/jsp/ suffix: .jsp
2.6整合mybatis,添加mapper.xml的目錄
mybatis: mapper-locations: classpath:mapper/*.xml
2.7整個yml文件如下
spring:
datasource:
url: jdbc:mysql://127.0.0.1:3306/springboot?useUnicode=true&characterEncoding=utf-8 driver-class-name: com.mysql.jdbc.Driver username: root password: 123456 mvc: view: prefix: /WEB-INF/jsp/ suffix: .jsp mybatis: mapper-locations: classpath:mapper/*.xml
2.8實體類的編寫,也就是model
和數據表對應的User類
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public class User {
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private int id;
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private String loginname;
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private String password;
//省略構造方法和get/set方法
}
返回數據給頁面的封裝類ResultEntity
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public class ResultEntity {
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private int code;
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private String message;
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//省略構造方法和get/set方法
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}
2.9 控制層的編寫,controller
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public class LoginController {
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private LoginService loginService;
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public String index() {
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return "login";
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}
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public String success() {
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return "success";
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}
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public ResultEntity login(User user, Model model) {
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ResultEntity resultEntity = loginService.login(user);
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if (resultEntity.getCode() == 200)
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model.addAttribute( "user", user);//將user存放到session
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return resultEntity;
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}
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}
2.10Service實現層的編寫
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class LoginServiceImpl implements LoginService {
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private UserMapper userMapper;
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private ResultEntity resultEntity;
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public ResultEntity login(User user) {
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User login = userMapper.login(user);
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if (login != null) {
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resultEntity = new ResultEntity(200, "登陸成功");
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} else {
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resultEntity = new ResultEntity(201, "用戶名或密碼錯誤");
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}
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return resultEntity;
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}
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}
接口層就忽略啦 我懶。。就一個 ResultEntity login(User user);
2.11 mapper.xml
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<mapper namespace="net.stxy.boot.dome.mapper.UserMapper">
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<select id="login" parameterType="net.stxy.boot.dome.model.User" resultType="net.stxy.boot.dome.model.User">
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select * from tuser where loginname = #{loginname} and password = #{password}
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</select>
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</mapper>
mapper接口也不寫了。。。QAQ..
2.12 到頁面了,采用jsp開發,所以要在pom.xml中添加對jsp的支持
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<!--springboot tomcat jsp 支持開啟-->
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<dependency>
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<groupId>org.apache.tomcat.embed</groupId>
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<artifactId>tomcat-embed-jasper</artifactId>
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</dependency>
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<dependency>
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<groupId>javax.servlet</groupId>
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<artifactId>jstl</artifactId>
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<scope>compile</scope>
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</dependency>
因為在yml中指定了前端控制器,所以直接在WEB-INF的jsp下讀取jsp頁面,靜態資源文件就可以在路徑前面添加,例如jquery文件放在static/js/jquery.min.js,讀取直接讀js/jquery.min.js即可,因為默認靜態資源路徑為/static/
2.13 登陸頁面用ajax提交表單,判斷返回的code是否==200,等於200則跳轉登陸成功頁面,否則,提示失敗.
ajax代碼:
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//提交表單
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$.ajax({
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url: "/login",
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type: "post",
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dataType: "json",
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data: {
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loginname: account,
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password: password
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},
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success: function (result) {
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console.log(result);
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if (result.code == 200) {
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window.location.href = "success";
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} else {
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alert(result.message);
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}
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}
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})
3.效果
3.1地址欄輸入 localhost:8080/index,出現登陸頁面

3.2登陸失敗

3.3登陸成功

這是一個非常簡單的springboot登陸例子,新手一枚,勿噴i....QAQ...
