python 實現：題目：有n個人圍成一圈，順序排號。從第一個人開始報數（從1到3報數），凡報到3的人退出圈子，問最后留下的是原來第幾號的那位

 

count = int(input('Please input the count:'))
li = []
for i in range(count):
    li.append(i+1)
times = count//3 +2
count_tial = 0
for i in range(times):
    for j in range(count_tial+1,len(li)+count_tial+1):
        if count_tial == 2:
            li[0] = 0
        if (j - count_tial) < len(li) and (j+1)%3 == 0:
            li[j - count_tial] = 0
    count_0 = li.count(0)
    try:
        count_tial = len(li) - li.index(0,len(li)-3,len(li))-1
    except Exception as e:
        break
    for i in range(len(li)):
        try:
            li.remove(0)
        except:pass
if len(li) == 2:
    print('\n   ! ! ! The last is:',li[1],' ! ! !')
else:print('\n   ! ! ! The last is:',li[0],' ! ! !')
# print('\n(last li:',li,')')

 參考https://blog.csdn.net/cuipengchong/article/details/38760127