登錄后保存用戶信息到Session

 

前端通過JS把用戶信息傳到Controller，然后在Controller里將信息放入HttpSession中

1.  
   @ResponseBody
2.  
   @RequestMapping(value = "/loginIn", method = RequestMethod.POST, produces = "application/json;charset=UTF-8")
3.  
   public String loginIn(HttpServletRequest request, HttpSession httpSession) {
4.  
   String loginuser = request.getParameter( "username");
5.  
   String pwd = request.getParameter( "password");
6.  
   logger.info( "loginuser:" + loginuser + ",pwd:" + pwd);
7.  
   JSONObject jsonObject = userFacade.loginIn(loginuser, pwd);
8.  
   // 將用戶保存到session內
9.  
   if ( "0".equals(jsonObject.getString( "ecode"))) { //判斷不用管
10.  
    httpSession.setAttribute( "username", loginuser);
11.  
    httpSession.setAttribute( "password", pwd);
12.  
    }
13.  
    return FastJsonConvert.convertObjectToJSON(jsonObject);
14.  
    }

再在前端js中調用Controller第二個方法，獲取session內容

JS中代碼：

1.  
   var username = "";
2.  
   $.ajax({
3.  
   "url" : "getUserSession",
4.  
   "method" : "POST",
5.  
   "cache" : false,
6.  
   "async" : false,
7.  
   }).success( function(data){
8.  
   if(data.username != null){
9.  
   username = data.username;
10.  
    }
11.  
    })

Controller獲取代碼：（return JSON對象）

 

1.  
   @ResponseBody
2.  
   @RequestMapping(value = "/getUserSession", method = RequestMethod.POST, produces = "application/json;charset=UTF-8")
3.  
   public String getUserSession(HttpServletRequest request, HttpSession httpSession) {
4.  
   JSONObject jsonObject = new JSONObject();
5.  
   if(httpSession!= null){
6.  
   jsonObject.put( "username", httpSession.getAttribute( "username"));
7.  
   jsonObject.put( "password", httpSession.getAttribute( "password"));
8.  
   }
9.  
   return FastJsonConvert.convertObjectToJSON(jsonObject);
10.  
    }

這樣就可把user信息保存到session中，並返回到前端