查詢方法(3.0.3)
1.查詢一個員工的數據

1 @Test 2 public void selectMethod() throws SQLException { 3 4 // 根據ID獲取一個對象的數據 5 Employee employee = employeeMapper.selectById(1); 6 7 if (employee!=null) { 8 logger.info("++一個員工信息+++++"+gson.toJson(employee)); 9 } 10 11 }
2.查詢的字段設置

1 @Test 2 public void selectMethod() throws SQLException { 3 4 // select 要查詢的字段 5 // SELECT email FROM tbl_employee 6 List<Employee> employeeList = employeeMapper.selectList(new QueryWrapper<Employee>().select("email")); 7 8 9 10 if (!employeeList.isEmpty()) { 11 logger.info("++一個員工信息+++++"+gson.toJson(employeeList)); 12 } 13 14 15 }
相當於執行SELECT email FROM tbl_employee 這條sql語句
3.拼接where多條件和order by方法時候,不需要的可以直接去掉

1 @Test 2 public void selectMethod() throws SQLException { 3 4 Employee employee = new Employee(); 5 6 // where 條件查詢和and添加和orderby使用 7 // SELECT age FROM tbl_employee WHERE email = ? AND age = ? ORDER BY id ASC 8 List<Employee> employeeList = employeeMapper.selectList(new QueryWrapper<Employee>().select("age").eq("email",employee.getEmail()).eq("age",employee.getAge()).orderBy(true,true,"id")); 9 10 11 if (!employeeList.isEmpty()) { 12 logger.info("++一個員工信息+++++"+gson.toJson(employeeList)); 13 } 14 15 16 }
相當於SQL語句SELECT age FROM tbl_employee WHERE email = ? AND age = ? ORDER BY id ASC
4.批量查詢

1 @Test 2 public void selectMethod() throws SQLException { 3 4 List<Integer> idList = new ArrayList<>(); 5 idList.add(1); 6 idList.add(2); 7 8 List<Employee> employeeList =employeeMapper.selectBatchIds(idList); 9 10 11 if (!employeeList.isEmpty()) { 12 logger.info("++一個員工信息+++++"+gson.toJson(employeeList)); 13 } 14 15 16 }
相當於SQL語句SELECT id,last_name,email,gender,age FROM tbl_employee WHERE id IN ( ? , ? )
5.Map查詢封裝

1 @Test 2 public void selectMethod() throws SQLException { 3 4 Employee employee = employeeMapper.selectById(1); 5 6 Map<String,Object> map = new HashMap<>(16); 7 map.put("email",employee.getEmail()); 8 map.put("age",employee.getAge()); 9 10 11 List<Employee> employeeList =employeeMapper.selectByMap(map); 12 13 if (!employeeList.isEmpty()) { 14 logger.info("++一個員工信息+++++"+gson.toJson(employeeList)); 15 } 16 17 18 }
相當於SQL語句SELECT id,last_name,email,gender,age FROM tbl_employee WHERE email = ? AND age = ?
結果封裝成map

1 ++一個員工信息+++++[{"id":1,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":2,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":3,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":4,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":12,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":13,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":14,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":15,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":16,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":17,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":18,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":19,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":20,"lastName":"Marry","email":"1","gender":0,"age":55},{"id":21,"lastName":"Marry","email":"1","gender":0,"age":55}] (TestCRUD.java:146)