表tariff_info, 原始數據:

想要的結果:以start_time時間倒序排序, 以code分類, 查詢每一類最新的一條記錄

sql:
SELECT a.* FROM TARIFF_INFO a, ( SELECT code, MAX (start_time) start_time FROM TARIFF_INFO GROUP BY code ) b WHERE a.start_time = b.start_time AND a.code = b.code ORDER BY a.code
這樣查詢結果已經實現了, 但是需要添加過濾條件, 即當前時間在start_time和end_time之間. 如果還用上面的sql僅僅在末尾追加一個條件發現查詢結果為空:

所以必須在子查詢中添加同樣的過濾條件方可查出正確結果, 如下面sql:
SELECT a.* FROM TARIFF_INFO a, ( SELECT code, MAX (start_time) start_time FROM TARIFF_INFO WHERE start_time <= '2018-09-18' GROUP BY code ) b WHERE a.start_time = b.start_time AND a.code = b.code AND a.start_time <= '2018-09-18' ORDER BY a.code

另:需要注意sql中時間區間的比較<=貌似有臨界日期會漏掉的情況, 這里不作贅述了.以下sql和上面的異曲同工:
SELECT a.* FROM TARIFF_INFO a INNER JOIN ( SELECT code, MAX (start_time) 'start_time' FROM TARIFF_INFO WHERE CONVERT(VARCHAR(10),start_time,121) <= '2018-09-18' GROUP BY code ) b ON a.code = b.code AND a.start_time = b.start_time AND CONVERT(VARCHAR(10),b.start_time,121) <= '2018-09-18' ORDER BY a.code
感謝:https://blog.csdn.net/sinat_27693393/article/details/78673971
