字符串有很多操作,目前先不講什么\(KMP\),\(AC\)自動機之類的高端算法。我感覺字符串的操作對於\(OIer\)們比較薄弱,特別是轉\(C++\)的\(P\)黨們
便於本文閱讀,開頭省略以下代碼:
#include <cstdio>
#include <iostream>
#include <string>
#include <cstring>
using namespace std;
並且考慮到閱讀體驗,輸入輸出將不用\(latex\)
字符串的輸入輸出的一些常見誤區
\(string\)類型一般都是用\(cin\)讀入。
\(char\)類型用\(cin\),\(scanf\)或者\(sscanf\)讀入
一般字符串的題目都是模擬題,所以不用怕\(cin\)超時
1、\(cin\) 作用:讀到空格,\(Tab\),回車就結束讀入
\(char\)版:
int main()
{
char s[20];
cin>>s;
cout<<s<<endl;
return 0;
}
\(string\)版:
int main()
{
string s;
cin>>s;
cout<<s<<endl;
return 0;
}
\(Input\):abc def
\(Output\):abc
2、\(scanf\) 作用:同\(cin\)
\(char\)版:
int main()
{
char s[20];
scanf("%s",s);
printf("%s\n",s);
return 0;
}
\(Input\):abc def
\(Output\):abc
3、\(getline\) 作用:讀入整行字符串,碰到換行退出
\(string\)版:
int main()
{
string s;
getline(cin,s);
cout<<s<<endl;
return 0;
}
\(Input\):abc def
\(Output\):abc def
4、\(cin.get\) 作用:讀入單個字符,類型必須是\(char\)
int main()
{
char s;
s=cin.get();
cout<<s<<endl;
return 0;
}
\(Input\):abc def
\(Output\):a
5、\(getchar\) 作用:讀入單個字符,類型必須是\(char\)
int main()
{
char s;
s=getchar();
cout<<s<<endl;
return 0;
}
\(Input\):abc def
\(Output\):a
輸出有幾種方式,\(cout\),\(printf\),\(putchar\),不過我覺得\(gets\)和\(puts\)要盡量少用,有些題目用\(gets\)會因為\(Linux\)的一些原因導致程序\(WA\)
順帶提一句,除\(puts\)會輸出自動換行,其他三種輸出方式不會自動換行
正文
筆者羅列了一下字符串的基本操作:
字符串操作:賦值,復制,連接,比較,清空
字符串性質:求串長,求子串,查找子串,刪除,替換,插入
字符串狀態:判定串是否為空
那么我們從字符串的操作講起吧
1、賦值
(1) \(=\)
單個字符用單引號'',多個字符用雙引號""
int main()
{
char s1[20]="What?!",s2='W';
cout<<s1<<" ";
cout<<s2<<endl;
return 0;
}
\(Output\): What?! W
(2)\(push_back\)
這是\(string\)特有的,因為直接賦值單字符''會\(CE\),用法即在字符串末尾添加一個字符
int main()
{
string s;
s.push_back('W');
cout<<s<<endl;
return 0;
}
\(Output\):W
(3) \(memset\)
memset(s,c,len) 將字符串\(s\)前\(len\)的字符初始化為\(char\)類型\(c\)
int main()
{
char s[20];
memset(s,'0',sizeof(s)+1);//不+1結尾會輸出一個問號
cout<<s<<endl;
return 0;
}
\(Output\):0000000000000000000
2、復制
\(char\)類型:
(1) \(memcpy\)
memcpy(s1,s2,len) 將\(s2\)復制\(len\)長度到\(s1\)
int main()
{
char s1[20],s2[20]="What?!",s3[20]="Aha!";
memcpy(s1,s2,strlen(s2)+1);//將s2復制到s1
cout<<s1<<" ";
memcpy(&s1,&s3,sizeof(s3));;//將s3復制到s1
cout<<s1<<endl;
return 0;
}
\(Output\): What?! Aha!
(2) \(strcpy\)
strcpy(s1,s2) 將\(s2\)復制到\(s1\)上
int main()
{
char s1[20],s2[20]="What?!";
strcpy(s1,s2);//將s2復制到s1
cout<<s1<<" ";
strcpy(s1,"Aha!");//將"Aha!"復制到s1
cout<<s1<<endl;
return 0;
}
\(Output\): What?! Aha!
(3)\(strncpy\)
strncpy(s1,s2,len) 將\(s2\)復制\(len\)長度到\(s1\)
int main()
{
char s1[20]={0},s2[20]={0},s3[20]="What?!";//這里不初始化會出現奇怪的東西
strncpy(s1,s3,sizeof(s3));//將s3復制到s1
cout<<s1<<" ";
strncpy(s2,s3,4);//將s3開始的4個字符復制到s2
cout<<s2<<endl;
return 0;
}
\(Output\): What?! Aha!
\(string\)類型:
(1) \(=\)
直接等於另一個字符串
int main()
{
string s1,s2="What?!";
s1=s2;
cout<<s1<<endl;
return 0;
}
\(Output\):What?!
(2) \(copy\)
s1.copy(s,len,s) 復制\(s1\)第\(l\)個位置,長度為\(len\)到字符串\(s\),但是\(s\)是\(char\)類型
int main()
{
string s1="Code is King";
char s[6];s1.copy(s,7,5);
cout<<s<<endl;
return 0;
}
如果定義字符數組大於所要\(copy\)的長度,會出現奇怪的東西,所以要手動算長度
3、連接
\(char\)類型:
(1)\(strcat\)
strcat(s1,s2) 在\(s1\)后拼接\(s2\)
int main()
{
char s1[20]="Code is",s2[20]=" King";
strcat(s1,s2);//在s1后拼接s2
cout<<s1<<endl;
return 0;
}
\(Output\):Code is King
(2)\(strncat\)
strncat(s1,s2,len) 在\(s1\)后面拼接\(s2\)的前\(len\)個字符
int main()
{
char s1[20]="Code is",s2[20]=" King Code";
strncat(s1,s2,5);//在s1后面接上s2開始的5個字符
cout<<s1<<endl;
return 0;
}
\(Output\):Code is King
\(string\)類型:
(1) +=
由於\(string\)里面有\(operator\),所以直接\(+=\)就行了
int main()
{
string s1="Code is",s2=" King";
s1+=s2;//直接接上
cout<<s1<<endl;
return 0;
}
\(Output\):Code is King
4、比較
\(char\)類型:
(1) \(strcmp\)
strcmp(s1,s2) 若s1>s2,返回一個正數;若s1==s2,返回\(0\),若s1<s2 返回一個負數
怎么判定一個串比較和另一個串的大小呢?\(C++\)是比較第一次失配時兩個字符\(ASCLL\)碼的大小,一個串是另一個串的前綴,那么另一個串大
int main()
{
char s1[20]="Code is King";
char s2[20]="Code is King";
char s3[20]="Code is Queen";
cout<<strcmp(s1,s2)<<" ";//比較大小
cout<<strcmp(s1,s3)<<endl;
return 0;
}
\(Output\):0 -1
(2) \(strncmp\)
strncmp(s1,s2,len) 比較\(s1\)和\(s2\)的前\(len\)個字符,若s1>s2,返回一個正數;若s1==s2,返回\(0\),若s1<s2 返回一個負數
int main()
{
char s1[20]="Code is King";
char s2[20]="Code is Queen";
cout<<strncmp(s1,s2,8)<<" ";//比較s1和s2的前8個字符
return 0;
}
\(Output\):0
\(string\)類型
(1) \(>\ =\ <\)
原理同\(string\)中的\(=\),比較方式同\(strcmp\)
int main()
{
string s1="Code is King";
string s2="Code is King";
string s3="Code is Queen";
if(s1==s2) cout<<0<<" ";//直接比較
else cout<<-1<<" ";
if(s2==s3) cout<<0<<endl;
else cout<<-1<<endl;
return 0;
}
\(Output\):0 -1
5、清空
\(char\)類型: 可以直接一位一位賦值,或者直接\(memset\),用法略
\(string\)類型:
(1) \(clear\)
s.clear() 清空原串
int main()
{
string s="Code is King";
s.clear();//清空
cout<<s<<endl;
return 0;
}
\(Output\):啥都不輸出
(2) 直接等於一個空串,用法略
接下來就是字符串性質
1、求串長
\(char\)類型:
(1) \(strlen\)
strlen(s) 返回字符串\(s\)的長度
int main()
{
char s[20]="Code is King";
cout<<strlen(s)<<endl;//求s的長度
return 0;
}
\(Output\):12
\(string\)類型:
(1) \(s.length\)
s.length() 返回字符串\(s\)的長度
int main()
{
string s="Code is King";
cout<<s.length()<<endl;//求s的長度
return 0;
}
\(Output\):12
\(Tips\):如果你平常用這種方法寫輸出請改一下
for(int i=0;i<strlen(s);i++)
cout<<s[i];
cout<<endl;
因為每一次都要算一個\(strlen\),所以復雜度成為了\(O(n^2)\)
2、求子串
\(char\)類型:直接\(strnpy\),用法略
\(string\)類型:
(1) \(s.substr\)
s,substr(l,len) 復制串\(s\)從第\(l\)個字符開始\(len\)長度的串
s.substr(l) 復制串\(s\)到末尾
int main()
{
string s1="Code is King";
string s2=s1.substr(5,7);//復制從第5個字符開始的7個字符
string s3=s1.substr(5);//復制從第5個字符開始直到末尾
cout<<s2<<" ";
cout<<s3<<endl;
return 0;
}
\(Output\):is King is King
3、查找子串
\(char\)類型
(1) \(strstr\)
strstr(s1,s2) 查找\(s2\)\(s1\)第一次中指針地址,若找不到,指針地址為\(end\)
int main()
{
char s[20]="Code is King";
char *p=strstr(s,"is");//在s中查找is並返回指針
cout<<p<<endl;
return 0;
}
\(Output\):is King
(2) \(strnstr\) 反向查找\(s2\)在\(s1\)第一次的指針地址,若找不到,指針地址為\(end\),用法略
\(string\)類型:
(1) \(find\)
s.find(s1) 查找串\(s1在串\)s\(中\)第一次出現的位置,若找不到,值為\(s.end()\)
int main()
{
string s="Code is King";
int find=s.find("is");//查找s中的is
cout<<find<<endl;
return 0;
}
\(Output\):5
(2) \(rfind\)
s.rfind(s1) 反向查找串\(s1在串\)s\(中\)第一次出現的位置,若找不到,值為\(s.end()\)
int main()
{
string s="Code is King";
int find=s.rfind("is");//反向查找is
cout<<find<<endl;
return 0;
}
\(Output\):5
4、刪除
\(string\)類型:
(1) \(erase\)
s,erase(l,len) 刪除串\(s\)從第\(l\)個字符開始\(len\)長度的串
s.erase(l) 刪除第\(l\)個字符
s.erase(l,r) 刪除\([l,r]\)區間內的字符
int main()
{
string s="This is an example sentence.";
cout<<s<<'\n'; //This is a example sentence.
s.erase(10,8);
cout<<s<<'\n'; //This is an sentence.
s.erase(s.begin()+9);
cout<<s<<'\n'; //This is a sentence.
s.erase(s.begin()+5, s.end()-9);
cout<<s<<'\n'; //This sentence.
return 0;
}
\(Output\):
This is a example sentence.
This is an sentence.
This is a sentence.
This sentence.
\((Code\ By\ Reference\ C++)\)
5、替換
\(string\)類型:
(1) \(replace\)
s.replace(l,len,s1) 將串\(s\)中第\(l\)個字符開始\(len\)長度替換為串\(s1\)
s.replace(l1,len1,s1,l2,len2) 將串\(s\)中第\(l1\)個字符開始\(len1\)長度替換為串\(s1\)中第\(l2\)個字符開始\(len2\)長度
s.replace(l1,len1,s1,len2) 將串\(s\)中第\(l1\)個字符開始\(len1\)長度替換為串\(s1\)前\(len2\)長度
s.replace(l1,len1,len2,c) 將串\(s\)中第\(l1\)個字符開始\(len1\)長度替換為\(len2\)個\(c\)字符 \(c\)是\(char\)類型
int main()
{
string base="this is a test sing.";
string s2="n example";
string s3="sample phrase";
string s4="useful.";
// Using positions:
sing s=base; // "this is a test sing."
s.replace(9,5,s2); // "this is an example sing." (1)
s.replace(19,6,s3,7,6); // "this is an example phrase." (2)
s.replace(8,10,"just a"); // "this is just a phrase." (3)
s.replace(8,6,"a shorty",7); // "this is a short phrase." (4)
s.replace(22,1,3,'!'); // "this is a short phrase!!!" (5)
// Using iterators:
s.replace(s.begin(),s.end()-3,s3); // "sample phrase!!!" (1)
s.replace(s.begin(),s.begin()+6,"replace"); // "replace phrase!!!" (3)
s.replace(s.begin()+8,s.begin()+14,"is coolness",7); // "replace is cool!!!" (4)
s.replace(s.begin()+12,s.end()-4,4,'o'); // "replace is cooool!!!" (5)
s.replace(s.begin()+11,s.end(),s4.begin(),s4.end());// "replace is useful." (6)
cout<<s<<endl;
return 0;
}
\(Output\):replace is useful
\((Code\ by\ Reference\ C++)\)
6、插入
\(string\)類型:
(1) \(insert\)
s.insert(l,s1) 將串\(s1\)插入到串\(s\)第\(l\)個字符后
s.insert(l1,s1,l2,len) 將串\(s1\)第\(l2\)個字符開始\(len\)長度插入到串\(s\)第\(l1\)個字符后
s.insert(l,s1,len) 將串\(s1\)前\(len\)個字符插入到串\(s\)第\(l\)個字符后
s.insert(l,len,c) 將串\(s\)第\(l\)個字符后插入\(len\)個\(c\)字符 \(c\)是\(char\)類型
int main()
{
string s="to be question";
string s2="the ";
string s3="or not to be";
string::iterator it;
s.insert(6,s2); // to be (the )question
s.insert(6,s3,3,4); // to be (not )the question
s.insert(10,"that is cool",8); // to be not (that is )the question
s.insert(10,"to be "); // to be not (to be )that is the question
s.insert(15,1,':'); // to be not to be(:) that is the question
it = s.insert(s.begin()+5,','); // to be(,) not to be: that is the question
s.insert(s.end(),3,'.'); // to be, not to be: that is the question(...)
s.insert(it+2,s3.begin(),s3.begin()+3); // (or )
cout<<s<<endl;
return 0;
}
\(Output\): to be, or not to be: that is the question...
\((Code\ by\ Reference\ C++)\)
最簡單的字符串狀態留在最后
1、是否為空
\(string\)類型:
(1) \(empty\)
s.empty() 判定串\(s\)是否為空串,是返回\(1\),不是返回\(0\)
int main()
{
string s1="Code",s2;
if(!s1.empty()) cout<<1<<" ";
else cout<<0<<" ";
if(!s2.empty()) cout<<1<<endl;
else cout<<0<<endl;
return 0;
}
\(Output\):1 0
當然\(string\)里面還有一些函數如\(append\),\(assign\),筆者就不在此贅筆了
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