Thinkphp5 表單提交額外參數和頁面跳轉參數傳遞url

1. 表單提交

<input type="hidden" name="project_name" value="$project_name"/>

在控制器中獲取

$project_name=input("post.project_name");

 

2. php中跳轉

$this->success('新增項目成功',url("Version/index",array('project_name'=>$project_name)));die;