django 3種返回json方法
1.手動組裝字典返回
from django.http import JsonResponse, HttpResponse
from django.shortcuts import render
from app01.models import Book
# Create your views here.
def get_book(request):
all_book = Book.objects.all()
d = []
for i in all_book:
d.append({'name': i.name})
return JsonResponse(d, safe=False)
2.JsonResponse返回
def get_book2(request):
from django.forms.models import model_to_dict
all_book = Book.objects.all()
d = []
for i in all_book:
d.append(model_to_dict(i)) # <-------針對一個對象()
return JsonResponse(d, safe=False) # 非字典要設置成false
一般自己的系統會從別的系統獲取數據, 這里應該也僅限於展示, 所以JsonResponse還是有很多實用場景
def booapi(request):
from django.core.serializers import serialize
book_list = [
{'id': 1, 'name': 'ptyhon'},
{'id': 2, 'name': 'go'},
]
import json
return HttpResponse(json.dumps(book_list), content_type='application/json')
3.django自帶的serializers返回
這個好像只能針對queryset操作,即本地db里的數據,不能操作從其他系統api獲取到的list ,dict等
def get_book3(request):
from django.core.serializers import serialize
d = serialize('json', Book.objects.all()) # <-------針對一個queryset,[{}, {}]
# return HttpResponse(d)
return HttpResponse(d)
return render(request, 'myapp/index.html', {'foo': 'bar',}, content_type='application/xhtml+xml')
return HttpResponse(t.render(c, request), content_type='application/xhtml+xml')
return HttpResponse(json.dumps(data), content_type='application/json', status=400)
JsonResponse = HttpResponse+content-type
model轉dict方法
https://mp.weixin.qq.com/s/7gPLaCESHAB0dLgq7qZq5Q
使用類的__dict__方法
