mysql查詢每個部門/班級前幾名


Employee 表包含所有員工信息,每個員工有其對應的 Id, salary 和 department Id 。

+----+-------+--------+--------------+
| Id | Name  | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Henry | 80000  | 2            |
| 3  | Sam   | 60000  | 2            |
| 4  | Max   | 90000  | 1            |
| 5  | Janet | 69000  | 1            |
| 6  | Randy | 85000  | 1            |
+----+-------+--------+--------------+

Department 表包含公司所有部門的信息。

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

編寫一個 SQL 查詢,找出每個部門工資前三高的員工。例如,根據上述給定的表格,查詢結果應返回:

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| IT         | Randy    | 85000  |
| IT         | Joe      | 70000  |
| Sales      | Henry    | 80000  |
| Sales      | Sam      | 60000  |
+------------+----------+--------+

select d.Name Department,e1.Name Employee,e1.Salary
from Employee e1,Department d where e1.DepartmentId=d.Id and
(select count(distinct e2.Salary) from Employee e2 where e2.DepartmentId=d.Id and e2.Salary>e1.Salary)<3
order by d.Name,e1.Salary DESC

意思就是:我們要查詢的這個人,在這部門中工資比他高的少於3個人(0,1,2人)。
括號里面是查詢在這部門中工資比他高的人的數量。

 

找出每個部門工資最高的員工

select d.Name Department,e1.Name Employee,e1.Salary
from Employee e1,Department d where e1.DepartmentId=d.Id
and Salary in (select max(Salary) from Employee e2 where e1.DepartmentId=e2.DepartmentId)


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