jpa命名規則 jpa使用sql語句 @Query

關鍵字
方法命名
sql where字句

And
findByNameAndPwd
where name= ? and pwd =?

Or
findByNameOrSex
where name= ? or sex=?

Is,Equals
findById,findByIdEquals
where id= ?

Between
findByIdBetween
where id between ? and ?

LessThan
findByIdLessThan
where id < ?

LessThanEquals
findByIdLessThanEquals
where id <= ?

GreaterThan
findByIdGreaterThan
where id > ?

GreaterThanEquals
findByIdGreaterThanEquals
where id > = ?

After
findByIdAfter
where id > ?

Before
findByIdBefore
where id < ?

IsNull
findByNameIsNull
where name is null

isNotNull,NotNull
findByNameNotNull
where name is not null

Like
findByNameLike
where name like ?

NotLike
findByNameNotLike
where name not like ?

StartingWith

findByNameStartingWith
where name like '?%'

EndingWith
findByNameEndingWith
where name like '%?'

Containing
findByNameContaining
where name like '%?%'

OrderBy
findByIdOrderByXDesc
where id=? order by x desc

Not
findByNameNot
where name <> ?

In
findByIdIn(Collection<?> c)
where id in (?)

NotIn
findByIdNotIn(Collection<?> c)
where id not  in (?)

True

findByAaaTue

where aaa = true

False
findByAaaFalse
where aaa = false

IgnoreCase
findByNameIgnoreCase
where UPPER(name)=UPPER(?)

//where name in(?,?...) and age<?
public List<Employee> findByNameInAndAgeLessThan(List<String> names,Integer age);

在方法上加@Query就不需要遵守上面的規則了，可以進行自定義sql。

有兩種方式傳參：

@Query("select o from Employee o where o.name=?1 and o.age=?2")
public List<Employee> queryParams1(String name,Integer age);
@Query("select o from Employee o where o.name=:name and o.age=:age")
public List<Employee> queryParams2(@Param("name") String name, @Param("age") Integer age);

修改數據的時候需要使用到三個注解

@Modifying
@Query("update Employee o set o.age=:age where o.id=:id")
public void update(@Param("id") Integer id,@Param("age") Integer age);

首先是query這里需要加上@Modifying

但是僅僅加上這個會報錯，需要打開事務

所以還需要在service層方法上開啟事務，（service層開啟事務，事務會作用於整個查詢部分的方法）

@Transactional
public void update(Integer id,Integer age){
    employeeRepository.update(id,age);
}

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