swagger2 如何匹配多個controller

方法一：使用多個controller的共同擁有的父類，即精確到兩個controller的上一級

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.shubing"))
            .paths(PathSelectors.any())
            .build();
}

 

方法二：指定所有controller的都實現的一個接口，比如@RestController

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.withClassAnnotation(RestController.class))
            .paths(PathSelectors.any())
            .build();
}

 

 

使用以下兩種，都是錯誤的

@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.shubing.*.controller"))
            .paths(PathSelectors.any())
            .build();
}
@Bean
public Docket createRestApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .apiInfo(apiInfo())
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.shubing.course.controller"))
            .apis(RequestHandlerSelectors.basePackage("com.shubing.user.controller"))
            .paths(PathSelectors.any())
            .build();
}

 

 原創文章，歡迎轉載，轉載請注明出處！