練習8-2 計算兩數的和與差（10 分）

本題要求實現一個計算輸入的兩數的和與差的簡單函數。

函數接口定義：

void sum_diff( float op1, float op2, float *psum, float *pdiff );

其中op1和op2是輸入的兩個實數，*psum和*pdiff是計算得出的和與差。

裁判測試程序樣例：

#include <stdio.h>

void sum_diff( float op1, float op2, float *psum, float *pdiff );

int main()
{
    float a, b, sum, diff;

    scanf("%f %f", &a, &b);
    sum_diff(a, b, &sum, &diff);
    printf("The sum is %.2f\nThe diff is %.2f\n", sum, diff);
	
    return 0; 
}

/* 你的代碼將被嵌在這里 */

輸入樣例：

4 6

輸出樣例：

The sum is 10.00
The diff is -2.00

#include <stdio.h>

void sum_diff( float op1, float op2, float *psum, float *pdiff );

int main()
{
    float a, b, sum, diff;

    scanf("%f %f", &a, &b);
    sum_diff(a, b, &sum, &diff);
    printf("The sum is %.2f\nThe diff is %.2f\n", sum, diff);
    
    return 0; 
}

/* 你的代碼將被嵌在這里 */
 void sum_diff( float op1, float op2, float *psum, float *pdiff )
 {
     *psum=op1+op2;
     *pdiff=op1-op2;
 }