表關系
查詢練習

1、自行創建測試數據; 2、查詢學生總人數; 3、查詢“生物”課程和“物理”課程成績都及格的學生id和姓名; 4、查詢每個年級的班級數,取出班級數最多的前三個年級; 5、查詢平均成績最高和最低的學生的id和姓名以及平均成績; 6、查詢每個年級的學生人數; 7、查詢每位學生的學號,姓名,選課數,平均成績; 8、查詢學生編號為“2”的學生的姓名、該學生成績最高的課程名、成績最低的課程名及分數; 9、查詢姓“李”的老師的個數和所帶班級數; 10、查詢班級數小於5的年級id和年級名; 11、查詢班級信息,包括班級id、班級名稱、年級、年級級別(12為低年級,34為中年級,56為高年級),示例結果如下; 班級id 班級名稱 年級 年級級別 1 一年一班 一年級 低 12、查詢學過“張三”老師2門課以上的同學的學號、姓名; 13、查詢教授課程超過2門的老師的id和姓名; 14、查詢學過編號“1”課程和編號“2”課程的同學的學號、姓名; 15、查詢沒有帶過高年級的老師id和姓名; 16、查詢學過“張三”老師所教的所有課的同學的學號、姓名; 17、查詢帶過超過2個班級的老師的id和姓名; 18、查詢課程編號“2”的成績比課程編號“1”課程低的所有同學的學號、姓名; 19、查詢所帶班級數最多的老師id和姓名; 20、查詢有課程成績小於60分的同學的學號、姓名; 21、查詢沒有學全所有課的同學的學號、姓名; 22、查詢至少有一門課與學號為“1”的同學所學相同的同學的學號和姓名; 23、查詢至少學過學號為“1”同學所選課程中任意一門課的其他同學學號和姓名; 24、查詢和“2”號同學學習的課程完全相同的其他同學的學號和姓名; 25、刪除學習“張三”老師課的score表記錄; 26、向score表中插入一些記錄,這些記錄要求符合以下條件:①沒有上過編號“2”課程的同學學號;②插入“2”號課程的平均成績; 27、按平均成績從低到高顯示所有學生的“語文”、“數學”、“英語”三門的課程成績,按如下形式顯示: 學生ID,語文,數學,英語,有效課程數,有效平均分; 28、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分; 29、按各科平均成績從低到高和及格率的百分數從高到低順序; 30、課程平均分從高到低顯示(顯示任課老師); 31、查詢各科成績前三名的記錄(不考慮成績並列情況) 32、查詢每門課程被選修的學生數; 33、查詢選修了2門以上課程的全部學生的學號和姓名; 34、查詢男生、女生的人數,按倒序排列; 35、查詢姓“張”的學生名單; 36、查詢同名同姓學生名單,並統計同名人數; 37、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列; 38、查詢課程名稱為“數學”,且分數低於60的學生姓名和分數; 39、查詢課程編號為“3”且課程成績在80分以上的學生的學號和姓名; 40、求選修了課程的學生人數 41、查詢選修“王五”老師所授課程的學生中,成績最高和最低的學生姓名及其成績; 42、查詢各個課程及相應的選修人數; 43、查詢不同課程但成績相同的學生的學號、課程號、學生成績; 44、查詢每門課程成績最好的前兩名學生id和姓名; 45、檢索至少選修兩門課程的學生學號; 46、查詢沒有學生選修的課程的課程號和課程名; 47、查詢沒帶過任何班級的老師id和姓名; 48、查詢有兩門以上課程超過80分的學生id及其平均成績; 49、檢索“3”課程分數小於60,按分數降序排列的同學學號; 50、刪除編號為“2”的同學的“1”課程的成績; 51、查詢同時選修了物理課和生物課的學生id和姓名;
建立相關表

create table class_grade( gid int primary key auto_increment, gname varchar(16) not null unique ); create table class( cid int primary key auto_increment, caption varchar(16) not null, grade_id int not null, foreign key(grade_id) references class_grade(gid) ); create table student( sid int primary key auto_increment, sname varchar(16) not null, gender enum('女','男') not null default '女', class_id int not null, foreign key(class_id) references class(cid) ); create table teacher( tid int primary key auto_increment, tname varchar(16) not null ); create table course( cid int primary key auto_increment, cname varchar(16) not null, teacher_id int not null, foreign key(teacher_id) references teacher(tid) ); create table score( sid int not null unique auto_increment, student_id int not null, course_id int not null, score int not null, primary key(student_id,course_id), foreign key(student_id) references student(sid) on delete cascade on update cascade, foreign key(course_id) references course(cid) on delete cascade on update cascade ); create table teach2cls( tcid int not null unique auto_increment, tid int not null, cid int not null, primary key(tid,cid), foreign key(tid) references teacher(tid) on delete cascade on update cascade, foreign key(cid) references class(cid) on delete cascade on update cascade ); 建表
添加測試數據

# 5 個年級 insert into class_grade(gname) values ('一年級'), ('二年級'), ('三年級'), ('四年級'), ('五年級'); # 5 個老師 insert into teacher(tname) values ('張三'), ('李四'), ('王五'), ('李傑'), ('趙六'); # 12 個班級 insert into class(caption,grade_id) values ('一年一班',1), ('一年二班',1), ('一年三班',1), ('一年四班',1), ('一年五班',1), ('二年一班',2), ('二年二班',2), ('三年一班',3), ('三年二班',3), ('四年一班',4), ('四年二班',4), ('五年一班',5); # 10 個課程 insert into course(cname,teacher_id) values ('生物',1), ('體育',1), ('物理',2), ('化學',3), ('美術',4), ('音樂',2), ('語文',3), ('數學',4), ('地理',2), ('研究',1); # 18 個學生 insert into student(sname,gender,class_id) values # 12個學生 ('孫尚香','女',1), ('貂蟬','女',1), ('劉備','男',2), ('孫二娘','女',2), ('張飛','男',3), ('關羽','男',4), ('林黛玉','女',5), ('薛寶釵','女',6), ('宋江','男',6), ('白骨精','女',7), ('豬八戒','男',8), ('王熙鳳','女',1), ('李師師','女',2), ('金翠蓮','女',9), ('如花','女',1), ('沙僧','男',2), ('李美麗','女',3), ('金角大王','男',4); insert into score(student_id,course_id,score) values (1,1,60), (1,2,59), (1,3,58), (1,4,22), (1,5,59), (1,6,60), (1,7,99), (1,8,100), (1,9,88), (2,1,99), (2,2,99), (2,3,89), (2,4,60), (2,5,59), (2,6,33), (2,7,56), (2,8,59), (2,9,60), (3,1,59), (3,3,30), (3,5,28), (3,7,70), (3,9,60), (4,2,59), (4,4,100), (4,6,90), (4,8,80), (4,10,88), (5,1,59), (5,2,33), (5,3,12), (5,4,88), (6,1,60), (6,3,99), (6,5,100), (6,6,60), (6,7,59), (6,8,100), (6,9,88), (7,9,20), (7,1,36), (7,3,57), (7,5,60), (7,8,60), (7,10,60), (8,2,61), (8,4,59), (8,6,62), (9,8,59), (9,1,60), (9,2,61), (9,3,21), (10,1,70), (10,3,88), (10,5,68), (10,9,99), (11,1,89), (11,7,99), (12,3,100), (12,8,60); insert into teach2cls(tid,cid) values (1,1), (1,2), (1,3), (1,5), (2,4), (2,6), (2,8), (2,9), (2,1), (2,5), (3,7), (3,1), (3,3), (3,5), (3,9), (4,7), (4,2), (4,4), (4,6), (4,8), (4,1), (1,12), (2,12);
參考SQL
1、自行創建測試數據; 詳見"db5_結構+數據.sql" 2、查詢學生總人數; select count(sid) from student ; 3、查詢“生物”課程和“物理”課程成績都及格的學生id和姓名; select sid, sname from student where sid in( select score.student_id from score inner join course on score.course_id=course.cid where course.cname in( '生物', '物理' ) and score.score >= 60 group by score.student_id having count(course_id)=2 ); 4、查詢每個年級的班級數,取出班級數最多的前三個年級; select gname from class_grade where gid in ( select grade_id from class group by grade_id having count(cid) in ( select t1.count_cid from ( select distinct count(cid) as count_cid from class group by grade_id order by count_cid desc limit 3 ) as t1 ) ); 5、查詢平均成績最高和最低的學生的id和姓名以及平均成績; select student.sid, student.sname, t1.avg_score from student inner join ( select student_id, avg(score) as avg_score from score group by student_id having avg(score) in ( ( select avg(score) as max_avg_score from score group by student_id order by avg(score) desc limit 1 ), ( select avg(score) as min_avg_score from score group by student_id order by avg(score) asc limit 1 ) ) ) as t1 on student.sid = t1.student_id; 6、查詢每個年級的學生人數; select t1.grade_id, count(t1.sid) as count_student from ( select student.sid, class.grade_id from student inner join class on student.class_id=class.cid ) as t1 group by t1.grade_id; 7、查詢每位學生的學號,姓名,選課數,平均成績; select student.sid, student.sname, t1.count_course, t1.avg_score from student left join ( select student_id, count(course_id) as count_course, avg(score) as avg_score from score group by student_id ) as t1 on student.sid = t1.student_id; 8、查詢學生編號為“2”的學生的姓名、該學生成績最高的課程名、成績最低的課程名及分數; select student.sname, course.cname, t1.score from( select student_id, course_id, score from score where student_id=2 and score in( ( select min(score) from score where student_id=2 ), ( select max(score) from score where student_id=2 ) ) ) as t1 inner join student on t1.student_id=student.sid inner join course on t1.course_id=course.cid; 9、查詢姓“李”的老師的個數和所帶班級數; select teacher.tid, teacher.tname, t1.count_cid from teacher left join ( select tid, count(cid) as count_cid from teach2cls where tid in ( select tid from teacher where tname like '李%' ) group by tid ) as t1 on teacher.tid = t1.tid where teacher.tname like '李%'; 10、查詢班級數小於5的年級id和年級名; select gid, gname from class_grade where gid in ( select grade_id from class group by grade_id having count(caption)<5 ); 11、查詢班級信息,包括班級id、班級名稱、年級、年級級別(12為低年級,34為中年級,56為高年級),示例結果如下; 班級id 班級名稱 年級 年級級別 1 一年一班 一年級 低 # case when ... then select class.cid 班級id, class.caption 班級名稱, class_grade.gname 年級, case when class_grade.gid between 1 and 2 then '低' when class_grade.gid between 3 and 4 then '中' when class_grade.gid between 5 and 6 then '高' else 0 end as '年級級別' from class, class_grade where class.grade_id = class_grade.gid; 12、查詢學過“張三”老師2門課以上的同學的學號、姓名; select sid, sname from student where sid in ( select student_id from score where course_id in ( select course.cid from teacher, course where teacher.tid = course.teacher_id and teacher.tname = '張三' ) group by student_id having count(course_id) > 2 ); 13、查詢教授課程超過2門的老師的id和姓名; select tid, tname from teacher where tid in ( select teacher_id from course group by teacher_id having count(cid) > 2 ); 14、查詢學過編號“1”課程和編號“2”課程的同學的學號、姓名; select sid, sname from student where sid in ( select distinct student_id from score where course_id in ( 1, 2 ) ); 15、查詢沒有帶過高年級的老師id和姓名; select tid, tname from teacher where tid not in ( select tid from teach2cls where cid in ( select cid from class where grade_id in ( 5, 6 ) ) ); 16、查詢學過“張三”老師所教的所有課的同學的學號、姓名; select sid, sname from student where sid in ( select student_id from score inner join course on score.course_id=course.cid where teacher_id in( select sid from teacher where sname='張三' ) ) 17、查詢帶過超過2個班級的老師的id和姓名; select tid, tname from teacher where tid in ( select teacher_id from course group by teacher_id having count(cid) > 2 ); 18、查詢課程編號“2”的成績比課程編號“1”課程低的所有同學的學號、姓名; select sid, sname from student where sid in ( select t1.student_id from ( select student_id, score from score where course_id = 2 group by student_id ) as t1, ( select student_id, score from score where course_id = 1 group by student_id ) as t2 where t1.student_id = t2.student_id and t1.score < t2.score ); 19、查詢所帶班級數最多的老師id和姓名; # 考慮班級數並列最多的情況 select tid, tname from teacher where tid in ( select tid from teach2cls group by tid having count(cid) = ( select count(cid) from teach2cls group by tid order by count(cid) desc limit 1 ) ); 20、查詢有課程成績小於60分的同學的學號、姓名; select sid, sname from student where sid in ( select distinct student_id from score where score < 60 ); 21、查詢沒有學全所有課的同學的學號、姓名; select sid, sname from student where sid not in ( select student_id from score group by student_id having count(course_id) = ( select count(cid) from course ) ); 22、查詢至少有一門課與學號為“1”的同學所學相同的同學的學號和姓名; select sid, sname from student where sid in ( select student_id from score where course_id in ( select course_id from score where student_id = 1 ) group by student_id ); 23、查詢至少學過學號為“1”同學所選課程中任意一門課的其他同學學號和姓名; select sid, sname from student where sid in ( select student_id from score where course_id in ( select course_id from score where student_id = 1 ) group by student_id ) and sid != 1; 24、查詢和“2”號同學學習的課程完全相同的其他同學的學號和姓名; select sid, sname from student where sid in ( select score.student_id from score, ( select course_id from score where student_id = 2 ) as t1 where score.course_id = t1.course_id and score.student_id != 2 group by score.student_id having count(score.course_id) = ( select count(course_id) from score where student_id = 2 ) ); 25、刪除學習“張三”老師課的score表記錄; delete from score where course_id in ( select course.cid from course, teacher where course.teacher_id = teacher.tid and teacher.tname = '張三' ); 26、向score表中插入一些記錄,這些記錄要求符合以下條件:①沒有上過編號“2”課程的同學學號;②插入“2”號課程的平均成績; # 實際結果會和上面一題有沖突,張三老師所教的2號課程 insert into score(student_id,course_id,score) select t1.sid, 2, t2.avg_score from ( select sid from student where sid not in ( select student_id from score where course_id = 2 ) ) as t1, ( select avg(score) as avg_score from score where course_id = 2 ) as t2; 27、按平均成績從低到高顯示所有學生的“語文”、“數學”、“英語”三門的課程成績,按如下形式顯示: 學生ID,語文,數學,英語,有效課程數,有效平均分; # 有效成績含所有課程,包括語數英 select t1.student_id as 學生ID, (select score.score from score left join course on score.course_id = course.cid where course.cname = '語文' and score.student_id = t1.student_id) as 語文, (select score.score from score left join course on score.course_id = course.cid where course.cname = '數學' and score.student_id = t1.student_id) as 數學, (select score.score from score left join course on score.course_id = course.cid where course.cname = '音樂' and score.student_id = t1.student_id) as 英語, count(t1.course_id) as 有效課程數, avg(t1.score) as 有效平均分 from score as t1 group by t1.student_id order by avg(t1.score) asc; 28、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分; select course.cid as 課程ID, max(score.score) as 最高分, min(score.score) as 最低分 from course left join score on course.cid = score.course_id group by score.course_id; 29、按各科平均成績從低到高和及格率的百分數從高到低順序; select course_id, avg(score) as avg_score, sum(case when score.score > 60 then 1 else 0 end) / count(1) * 100 as 及格率 from score group by course_id order by avg(score) desc, 及格率 asc; 30、課程平均分從高到低顯示(顯示任課老師); select course.cname, t1.avg_score, teacher.tname from course, teacher, ( select course_id, avg(score) as avg_score from score group by course_id order by avg_score desc ) as t1 where course.cid = t1.course_id and course.teacher_id = teacher.tid order by t1.avg_score desc; 31、查詢各科成績前三名的記錄(不考慮成績並列情況) select score.sid, score.student_id, score.course_id, score.sid, t1.first_score, t1.second_score, t1.third_score from score inner join ( select s1.sid, (select score from score as s2 where s1.course_id = s2.course_id order by score desc limit 0,1) as first_score, (select score from score as s3 where s1.course_id = s3.course_id order by score desc limit 1,1) as second_score, (select score from score as s4 where s1.course_id = s4.course_id order by score desc limit 2,1) as third_score from score as s1 ) as t1 on score.sid = t1.sid where score.score in ( t1.first_score, t1.second_score, t1.third_score ); 32、查詢每門課程被選修的學生數; # 包含了沒有被選修的課程顯示0 select course.cid, ifnull(t1.count_students,0) as count_student from course left join ( select course_id, count(student_id) as count_students from score group by course_id ) as t1 on course.cid = t1.course_id; 33、查詢選修了2門以上課程的全部學生的學號和姓名; select sid, sname from student where sid in ( select student_id from score group by student_id having count(course_id) > 2 ); 34、查詢男生、女生的人數,按倒序排列; select gender, count(sid) as count_student from student group by gender order by count_student desc; 35、查詢姓“張”的學生名單; select student.sid, student.sname, student.gender, class.caption from student inner join class on student.class_id = class.cid where student.sname like '張%'; 36、查詢同名同姓學生名單,並統計同名人數; select sname, count(sname) as count_sname from student group by sname having count(sname) > 1; 37、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列; select course_id, avg(score) as avg_score from score group by course_id order by avg_score, course_id desc; 38、查詢課程名稱為“數學”,且分數低於60的學生姓名和分數; select student.sname, t1.score from student inner join ( select score.student_id, score.score from score inner join course on score.course_id = course.cid where course.cname = '數學' and score.score < 60 ) as t1 on student.sid = t1.student_id; 39、查詢課程編號為“3”且課程成績在80分以上的學生的學號和姓名; select sid, sname from student where sid in ( select student_id from score where course_id = 3 and score > 80 ); 40、求選修了課程的學生人數 select course_id, count(student_id) as count_student from score group by course_id; 41、查詢選修“王五”老師所授課程的學生中,成績最高和最低的學生姓名及其成績; # 教的課可能包含多門,按課程id來分的!包含了最高,最低成績相等的情況 select student.sname, t2.course_id, t2.score, t2.max_score, t2.min_score from student inner join ( select score.student_id, score.course_id, score.score, t1.max_score, t1.min_score from score, ( select course_id, max(score) as max_score , min(score) as min_score from score where course_id in ( select cid from course inner join teacher on course.teacher_id = teacher.tid where teacher.tname = '王五' ) group by course_id ) as t1 where score.course_id = t1.course_id and score.score in ( max_score, min_score ) ) as t2 on student.sid = t2.student_id; 42、查詢各個課程及相應的選修人數; # 包含了沒有被選修的課程顯示0 select course.cname, ifnull(t1.count_student,0) as count_student from course left join ( select course_id, count(student_id) as count_student from score group by course_id ) as t1 on course.cid = t1.course_id; 43、查詢不同課程但成績相同的學生的學號、課程號、學生成績; # 不同的學生之間,成績相同 這里有問題!! select distinct s1.student_id, s2.student_id, s1.course_id as s1_course_id, s2.course_id as s2_course_id, s1.score, s2.score from score as s1, score as s2 where s1.course_id != s2.course_id and s1.score = s2.score; select distinct # 同一個學生,成績相同 s1.student_id, s2.student_id, s1.course_id as s1_course_id, s2.course_id as s2_course_id, s1.score, s2.score from score as s1, score as s2 where s1.student_id = s2.student_id and s1.course_id != s2.course_id and s1.score = s2.score; 44、查詢每門課程成績最好的前兩名學生id和姓名; # 這個有排名 包括了成績相同的! select c.sname, d.cname, a.score from score a inner join ( select course_id, score, rank from ( select a.course_id, a.score, count(*) as rank from (select course_id, score from score group by course_id, score order by course_id, score desc) a inner join (select course_id, score from score group by course_id, score order by course_id, score desc) b on a.course_id = b.course_id and a.score <= b.score group by course_id, score ) t1 where rank in (1, 2) order by course_id, rank ) b on a.course_id = b.course_id and a.score = b.score inner join student c on a.student_id = c.sid inner join course d on a.course_id = d.cid; 45、檢索至少選修兩門課程的學生學號; select student_id from score group by student_id having count(course_id) >= 2; 46、查詢沒有學生選修的課程的課程號和課程名; select cid, cname from course where cid not in ( select course_id from score group by course_id ); 47、查詢沒帶過任何班級的老師id和姓名; select tid, tname from teacher where tid not in ( select tid from teach2cls group by tid ); 48、查詢有兩門以上課程超過80分的學生id及其平均成績; select student_id, avg(score) as avg_score from score where student_id in ( select student_id from score where score > 80 group by student_id having count(course_id) > 2 ) group by student_id; 49、檢索“3”課程分數小於60,按分數降序排列的同學學號; select student_id, score from score where course_id = 3 and score < 60 order by score desc; 50、刪除編號為“2”的同學的“1”課程的成績; delete from score where sid = ( select t1.sid from ( select sid from score where student_id = 2 and course_id = 1 ) as t1 ); 51、查詢同時選修了物理課和生物課的學生id和姓名; select sid, sname from student where sid in ( select student_id from score where course_id in ( select cid from course where course.cname in ( '物理', '生物' ) ) group by student_id having count(course_id) = 2 );