SELECT CASE WHEN (age >= 10 AND age <= 20) THEN '10-20' WHEN (age >= 21 AND age <= 30) THEN '21-30' ELSE '30-' END 'eag_layer', count(*) emps FROM address_book GROUP BY CASE WHEN (age >= 10 AND age <= 20) THEN '10-20' WHEN (age >= 21 AND age <= 30) THEN '21-30' ELSE '30-' END ORDER BY 1;
SELECT '10-20' 年齡段, COUNT(*) 人數 FROM [Table] WHERE [年齡] BETWEEN 10 AND 20 UNION ALL SELECT '21-30' 年齡段, COUNT(*) 人數 FROM [Table] WHERE [年齡] BETWEEN 21 AND 30 UNION ALL SELECT '31' 年齡段, COUNT(*) 人數 FROM [Table] WHERE [年齡] > 30
select case when [年齡] BETWEEN 10 AND 20 then '10-20' when [年齡] BETWEEN 20 AND 30 then '20-30' when [年齡] > 30 then '30以上' end as '年齡段', count(*) as '人數' FROM [Table]
先將年齡除10取整
select floor(年齡/10) as age from 表- 1
再根據年齡整數分組統計
select age ,count(age) from ( select floor(年齡/10) as age from 表 ) group by age
這樣基本效果就出來了，達到樓主的要求就要加如函數計算了
sql語法
select convert(varchar，age*10)+'--'+convert(varchar，(age+1)*10) ,count(age) from ( select floor(年齡/10) as age from 表 ) group by age
oracle語法
select age*10 || '--'|| (age+1)*10 ,count(age) from ( select floor(年齡/10) as age from 表 ) group by age