JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8: illegal start byte 0xfe

在使用Jni的JNIEnv->NewStringUTF的時候拋出了異常"JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8: illegal start byte 0xfe "。網上搜索了一下，這個異常是由於Java虛擬機內部的dalvik/vm/CheckJni.c中的checkUtfString函數拋出的，並且JVM的這個接口明確是不支持四個字節的UTF8字符。因此需要在調用函數之前，對接口傳入的字符串進行過濾，過濾函數如下：

checkUtfString

C++

int checkUtfString(const char* bytes) { const char* origBytes = bytes; if (bytes == NULL) { return -1; } while (*bytes != '\0') { unsigned char utf8 = *(bytes++); // Switch on the high four bits. switch (utf8 >> 4) { case 0x00: case 0x01: case 0x02: case 0x03: case 0x04: case 0x05: case 0x06: case 0x07: { // Bit pattern 0xxx. No need for any extra bytes. break; } case 0x08: case 0x09: case 0x0a: case 0x0b: case 0x0f: { /*printf("****JNI WARNING: illegal start byte 0x%x\n", utf8);*/ return -1; } case 0x0e: { // Bit pattern 1110, so there are two additional bytes. utf8 = *(bytes++); if ((utf8 & 0xc0) != 0x80) { /*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/ return -1; } // Fall through to take care of the final byte. } case 0x0c: case 0x0d: { // Bit pattern 110x, so there is one additional byte. utf8 = *(bytes++); if ((utf8 & 0xc0) != 0x80) { /*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/ return -1; } break; } } } return 0; }

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52

int checkUtfString(const char* bytes) {     const char* origBytes = bytes;     if (bytes == NULL) {         return -1;     }     while (*bytes != '\0') {        unsigned char utf8 = *(bytes++);         // Switch on the high four bits.         switch (utf8 >> 4) {             case 0x00:             case 0x01:             case 0x02:             case 0x03:             case 0x04:             case 0x05:             case 0x06:             case 0x07: {                 // Bit pattern 0xxx. No need for any extra bytes.                 break;             }             case 0x08:             case 0x09:             case 0x0a:             case 0x0b:             case 0x0f: {                 /*printf("****JNI WARNING: illegal start byte 0x%x\n", utf8);*/                 return -1;             }             case 0x0e: {                 // Bit pattern 1110, so there are two additional bytes.                 utf8 = *(bytes++);                 if ((utf8 & 0xc0) != 0x80) {                     /*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/                     return -1;                 }                 // Fall through to take care of the final byte.             }             case 0x0c:             case 0x0d: {                 // Bit pattern 110x, so there is one additional byte.                 utf8 = *(bytes++);                 if ((utf8 & 0xc0) != 0x80) {                     /*printf("****JNI WARNING: illegal continuation byte 0x%x\n", utf8);*/                     return -1;                 }                 break;             }         }     }     return 0; }

參考鏈接 android jni中 utf-8的check

發布者

 

默默

默默碼農 查看所有由默默發布的文章

 

 

#########################################################################################################

newStringUTF出現input is not valid Modified UTF-8錯誤解決辦法

2013年10月12日 ⁄ 綜合 ⁄ 共 883字 ⁄ 字號 小 中 大 ⁄ 評論關閉

 

JNI調用newStringUTF時遇到不認識的字符串就直接出錯退出~~,網上原因是dalvik/vm/CheckJni.c里面的checkUtfString函數檢查通不過.找了半天沒找到修正辦法,把這個函數改了下,當做一個修正函數,下面是代碼

 

void correctUtfBytes(char* bytes) {
  char three = 0;
   while (*bytes != '\0') {
	   unsigned char utf8 = *(bytes++);
	   three = 0;
	   // Switch on the high four bits.
	   switch (utf8 >> 4) {
	   case 0x00:
	   case 0x01:
	   case 0x02:
	   case 0x03:
	   case 0x04:
	   case 0x05:
	   case 0x06:
	   case 0x07:
		   // Bit pattern 0xxx. No need for any extra bytes.
		   break;
	   case 0x08:
	   case 0x09:
	   case 0x0a:
	   case 0x0b:
	   case 0x0f:
		   /*
			* Bit pattern 10xx or 1111, which are illegal start bytes.
			* Note: 1111 is valid for normal UTF-8, but not the
			* modified UTF-8 used here.
			*/
		   *(bytes-1) = '?';
		   break;
	   case 0x0e:
		   // Bit pattern 1110, so there are two additional bytes.
		   utf8 = *(bytes++);
		   if ((utf8 & 0xc0) != 0x80) {
			   --bytes;
			   *(bytes-1) = '?';
			   break;
		   }
		   three = 1;
		   // Fall through to take care of the final byte.
	   case 0x0c:
	   case 0x0d:
		   // Bit pattern 110x, so there is one additional byte.
		   utf8 = *(bytes++);
		   if ((utf8 & 0xc0) != 0x80) {
			   --bytes;
			   if(three)--bytes;
			   *(bytes-1)='?';
		   }
		   break;
	   }
   }
}

http://www.xuebuyuan.com/1240531.html
http://www.mobibrw.com/2016/2859