有如下值集合[11,22,33,44,55,66,77,88,99,100.110,200,230,330],
將所有大於66的值保存至字典的第一個key中,將等於小於66的值保存至第二個key中
即:{'k1':大於66,'k2':小於等於66}
實現的方式一:
all_list = [11,22,33,44,55,66,77,88,99,100.110,200,230,330]
dic = {}
list1 = [] #聲明列表
list2 = []
for i in all_list: #設置循環條件
if i>66:
list1.append(i)
else:
list2.append(i)
dic['k1'] = list1
dic['k2'] = list2
print(dic)
實現的方式二:
dic = {}
all_list = [11,22,33,44,55,66,77,88,99,100.110,200,230,330]
for i in all_list:
if i>66:
if "k1" in dic.keys(): #判斷是否存在K1
dic['k1'].append(i) #創建K1
else:
dic['k1'] = [i,] #在K1里面寫入列表i
else:
if "k2" in dic.keys(): #判斷是有存在K2
dic['k2'].append(i) #創建K2
else:
dic['k2'] = [i,] #在K2里面寫入列表i的數值
print(dic)
