MySQL實現排名並查詢指定用戶排名功能


表結構:
CREATE TABLE test.testsort ( id int(11) NOT NULL AUTO_INCREMENT, uid int(11) DEFAULT 0 COMMENT '用戶id', score decimal(10, 2) DEFAULT 0.00 COMMENT '分數', PRIMARY KEY (id) ) ENGINE = INNODB AUTO_INCREMENT = 1
CHARACTER SET utf8 COLLATE utf8_general_ci COMMENT = '測試排序' ROW_FORMAT = DYNAMIC;
 
思路:可以先排序,再對結果進行編號;也可以先查詢結果,再排序編號。
 
說明:
@rownum := @rownum + 1 中 := 是賦值的作用,這句話的意思是先執行@rownum + 1,然后把值賦給@rownum;
(SELECT @rownum := 0) r 這句話的意思是設置rownum字段的初始值為0,即編號從1開始。
 
實現排名:
方法一:
SELECT t.*, @rownum := @rownum + 1 AS rownum FROM (SELECT @rownum := 0) r, (SELECT * FROM testsort ORDER BY score DESC) AS t;
 
方法二:
SELECT t.*, @rownum := @rownum + 1 AS rownum FROM (SELECT @rownum := 0) r, testsort AS t ORDER BY t.score DESC;
 
結果:
 
 
查看指定用戶排名:
方法一:
SELECT b.* FROM ( SELECT t.*, @rownum := @rownum + 1 AS rownum FROM (SELECT @rownum := 0) r, (SELECT * FROM testsort ORDER BY score DESC) AS t ) AS b WHERE b.uid = 222;
 
方法二:
SELECT b.* from ( SELECT t.*, @rownum := @rownum + 1 AS rownum FROM (SELECT @rownum := 0) r, testsort AS t ORDER BY t.score DESC ) as b where b.uid = 222;
 
結果:
 
 
實現從指定用戶uid為111,222,333,444,555 中獲取uid為222的排名
SELECT b.* FROM ( SELECT t.*, @rownum := @rownum + 1 AS rownum FROM (SELECT @rownum := 0) r, (SELECT * FROM testsort WHERE uid IN (111,222,333,444,555) ORDER BY score DESC) AS t ) AS b WHERE b.uid = 222;

結果:


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