filter過濾器實現驗證跳轉_返回驗證結果

1. 需求背景

需要對某個請求url進行攔截，模擬是否可以進入某一個接口，如果攔截需要返回數據false，別問我為何不用intercept攔截器。

2. web.xml

<filter>    
    <filter-name>restfulFilter</filter-name>    
    <filter-class>com.jeenotes.utils.filter.RestfulFilter</filter-class> 過濾器路徑   
</filter>    

<filter-mapping>    
    <filter-name>restfulFilter</filter-name>    
    <url-pattern>/aaa/*</url-pattern>  aaa表示攔截的url,如果你想攔截所有，直接/*即可。   
</filter-mapping> 

 

3. 自定義的Filter

 public class RestfulFilter implements Filter { 

 private AAAService aaaService; @Override public void init(FilterConfig filterConfig) throws ServletException { } @Override public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { 
　　　　 //由於filter 優先級要高，所以直接@Autowired引入service是不存在的
 //如下是 HttpServletRequest req = (HttpServletRequest)request; HttpServletResponse resp = (HttpServletResponse)response; ServletContext sc = req.getSession().getServletContext();
 //如下是創建service過程 XmlWebApplicationContext cxt = (XmlWebApplicationContext)WebApplicationContextUtils.getWebApplicationContext(sc); //aaaServiceImpl 是aaaService實現類 if(cxt != null && cxt.getBean("aaaServiceImpl") != null && aaaService == null) aaaService = (AAAService) cxt.getBean("aaaServiceImpl"); //此處是邏輯 if(成功){ chain.doFilter(request, response); //進入請求的url }else{ req.getRequestDispatcher("/xxx某某url").forward(request,response);//跳轉自己指定的url } } @Override public void destroy() { } }

要跳轉的/xxx某某url

@RequestMapping(value = "/getEntranceStatus", method = RequestMethod.GET, produces = "text/html;charset=UTF-8")
    public String getEntranceStatus(HttpServletRequest request){
    
       //此處就是返回一個false
        
  }