oracle 日期格式化和數據去重

1、獲取系統日期：

select sysdate as date1 from dual；
   
當前時間減去7分鍾的時間   
select sysdate,sysdate - interval '7' MINUTE FROM dual;  
當前時間減去7小時的時間   
select sysdate,sysdate - interval '7' HOUR FROM dual;   
當前時間減去7天的時間   
select sysdate,sysdate - interval '7' DAY FROM dual;   
（select (sysdate-7) as date1 from dual）
當前時間減去7月的時間   
select sysdate,sysdate - interval '7' MONTH FROM dual;   
當前時間減去7年的時間   
select sysdate,sysdate - interval '7' YEAR FROM dual;   
時間間隔乘以一個數字   
select sysdate,sysdate - 8*interval '2' HOUR FROM dual;   

 

2、日期轉換方法：

to_date( '2020-01-01 13:14:20 ', 'yyyy-mm-dd hh24:mi:ss')

3、根據某個字段去重：

--I、Name相同ID最小的記錄(推薦用1,2,3),方法3在SQl05時，效率高於1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)
 
方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID
 
方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)
 
方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 
 
方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)
 
方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0
 
方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)
 
方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)
 
方法9(注:ID為唯一時可用):
select * from #T a where ID in(select min(ID) from #T group by Name)
 
--SQL2005:
 
方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID
 
方法11:
 
select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1