1 [0] => array(4) { 2 ["id"] => int(1) 3 ["bid"] => int(1) 4 ["sales"] => string(2) "15" 5 ["price"] => string(4) "5975" 6 } 7 [1] => array(4) { 8 ["id"] => int(2) 9 ["bid"] => int(1) 10 ["sales"] => string(1) "2" 11 ["price"] => string(3) "659" 12 } 13 [2] => array(2) { 14 ["id"] => int(3) 15 ["bid"] => int(1) 16 } 17 [3] => array(2) { 18 ["id"] => int(4) 19 ["bid"] => int(1) 20 } 21 [4] => array(4) { 22 ["id"] => int(5) 23 ["bid"] => int(1) 24 ["sales"] => string(1) "1" 25 ["price"] => string(3) "256" 26 }
我要根據bid把sales累加和price累加,人后去掉重復的bid只保留一個,方法:
1 $new = array(); 2 foreach ($store_i1 as $k=>$v){ 3 if(isset($new[$v['bid']])){ 4 $new[$v['bid']]['sales'] += $v['sales']; 5 $new[$v['bid']]['price'] += $v['price']; 6 }else{ 7 $new[$v['bid']]['sales'] = $v['sales']; 8 $new[$v['bid']]['price'] = $v['price']; 9 } 10 11 }
輸出結果:
1 [1] => array(2) { 2 ["sales"] => int(18) 3 ["price"] => int(6890) 4 } 5 [3] => array(2) { 6 ["sales"] => int(0) 7 ["price"] => int(0) 8 } 9 [2] => array(2) { 10 ["sales"] => string(3) "0" 11 ["price"] => string(5) "0" 12 }