yiled():讓步
wait():等待
sleep():休眠
yiled是讓步,會使當前線程由運行狀態進入到就緒狀態,讓其他優先級高線程先執行,但是如果是同一優先級的線程,那么誰先執行就不確定了.它不會釋放鎖
wailt等待,會使當前線程進入阻塞狀態,並且會釋放鎖
sleep()休眠,會使當前線程進入休眠阻塞狀態,但不會釋放鎖
下面通過示例演示sleep()是不會釋放鎖的。
1 // SleepLockTest.java的源碼
2 public class SleepLockTest{
3
4 private static Object obj = new Object();
5
6 public static void main(String[] args){
7 ThreadA t1 = new ThreadA("t1");
8 ThreadA t2 = new ThreadA("t2");
9 t1.start();
10 t2.start();
11 }
12
13 static class ThreadA extends Thread{
14 public ThreadA(String name){
15 super(name);
16 }
17 public void run(){
18 // 獲取obj對象的同步鎖
19 synchronized (obj) {
20 try {
21 for(int i=0; i <10; i++){
22 System.out.printf("%s: %d\n", this.getName(), i);
23 // i能被4整除時,休眠100毫秒
24 if (i%4 == 0)
25 Thread.sleep(100);
26 }
27 } catch (InterruptedException e) {
28 e.printStackTrace();
29 }
30 }
31 }
32 }
33 }
運行結果:
t1: 0 t1: 1 t1: 2 t1: 3 t1: 4 t1: 5 t1: 6 t1: 7 t1: 8 t1: 9 t2: 0 t2: 1 t2: 2 t2: 3 t2: 4 t2: 5 t2: 6 t2: 7 t2: 8 t2: 9
結果說明:
主線程main中啟動了兩個線程t1和t2。t1和t2在run()會引用同一個對象的同步鎖,即synchronized(obj)。在t1運行過程中,雖然它會調用Thread.sleep(100);但是,t2是不會獲取cpu執行權的。因為,t1並沒有釋放“obj所持有的同步鎖”!

