python處理dict轉json，字符串中存在空格問題，導致url編碼時，存在多余字符

在進行urlencode轉換請求的參數時，一直多出一個空格，導致請求參數不正確，多了一個空格，解決方法一種是將dict中key-value鍵值對的value直接定義為字符串，另一種是value仍然為字典，增加一部轉為json字符，之后再進行編碼，dict轉為json字符串也要注意空格問題，默認轉成的json字符串還是有多余的空格

# -*- coding: utf-8 -*-
import json
from urllib import parse

""" 
@version: v1.0 
@author: monleylu
@time: 2018/2/24 10:35 
"""
urlParam = {
    "c": {
        "cc": 3402,
        "ct": 10,
        "p": 14588,
        "ov": 20,
        "dt": 0,
        "v": "9.32.1"
    }
}
####
# 正常編碼結果應該為：
# c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D
# 可以看到多了個+ 加號
###
print("直接對字典進行編碼后結果:\r\n" + parse.urlencode(urlParam))



b = {"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}
# 可以看到默認格式參數化時，會多出一個空格
print("使用默認參數轉換dict到json字符串：\r\n" + json.dumps(b))

print("非默認參數轉換dict到json字符串：\r\n" + json.dumps(b, separators=(',', ':')))
a = {"c": json.dumps(b, separators=(',', ':'))}
print(parse.urlencode(a))

#一種解決方法
urlParam["c"]=json.dumps((urlParam["c"]),separators=(',', ':'))
print("進行編碼后結果:\r\n" + parse.urlencode(urlParam))

#另一種解決方法,這種方法仍然要注意字符串中間的空格，不是太推薦這種方法
urlParam = { "c": '{"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}'}
print("進行編碼后結果2:\r\n" + parse.urlencode(urlParam))

輸出結果
直接對字典進行編碼后結果:
c=%7B%27cc%27%3A+3402%2C+%27ct%27%3A+10%2C+%27p%27%3A+14588%2C+%27ov%27%3A+20%2C+%27dt%27%3A+0%2C+%27v%27%3A+%279.32.1%27%7D
使用默認參數轉換dict到json字符串：
{"cc": 3402, "ct": 10, "p": 14588, "ov": 20, "dt": 0, "v": "9.32.1"}
非默認參數轉換dict到json字符串：
{"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}
c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D
進行編碼后結果:
c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D
進行編碼后結果2:
c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D