1、a=a+2,表示一個新的對象,新的對象名字還是a,但是指向的內存地址已經變了
>>> a=2 >>> id(a) 140406287260016 >>> a=a+2 >>> a 4 >>> id(a) 140406287259968
所以對於tuple對象(不可變對象),也是可以這樣操作的
>>> tuple1=(1,2) >>> id(tuple1) 4521580448 >>> tuple1=tuple1+(3,) >>> tuple1 (1, 2, 3) >>> id(tuple1) 4521658880
2、a+=2對於有些對象的操作是表示原來的對象,對有些對象的操作是生成了一個新對象
不可變對象tuple1,操作完后,內存地址已經發生變化,生成一個新的對象
>>> tuple1=(1,2) >>> type(tuple1) <type 'tuple'> >>> tuple1+=(3,) >>> id(tuple1) 4521658880 >>> tuple1+=(4,5) >>> id(tuple1) 4520649072
而list對象,可變對象,+=操作、append操作、extend操作,都是在原對象上操作
>>> list1=[1,2] >>> id(list1) 4521614656 >>> list1+=[3] >>> id(list1) 4521614656 >>> list1.append(4) >>> id(list1) 4521614656 >>> list1.extend(5) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: 'int' object is not iterable >>> list1.extend([5]) >>> id(list1) 4521614656 >>>
3、
x = [1,2,3] print "before func(), global! x = ",x,"id(x) = ",id(x) def func(): global x print "in func(), local! original x = ",x,"id(x) = ",id(x) x = x + [1] print "in func(), local! now x = ",x,"id(x) = ",id(x) func() print "after func(), global! x = ",x,"id(x) = ",id(x) 結果: [python] view plain copy before func(), global! x = [1, 2, 3] id(x) = 47781768 in func(), local! original x = [1, 2, 3] id(x) = 47781768 in func(), local! now x = [1, 2, 3, 1] id(x) = 47795720 after func(), global! x = [1, 2, 3, 1] id(x) = 47795720
global就保證了,即使我的變量x在函數中指向對象變了,外部的x也會指向新的對象
x = [1,2,3] print "before func(), global! x = ",x,"id(x) = ",id(x) def func(x): print "in func(), local! original x = ",x,"id(x) = ",id(x) x = x + [1] print "in func(), local! now x = ",x,"id(x) = ",id(x) func(x) print "after func(), global! x = ",x,"id(x) = ",id(x) 結果: before func(), global! x = [1, 2, 3] id(x) = 46339976 in func(), local! original x = [1, 2, 3] id(x) = 46339976 in func(), local! now x = [1, 2, 3, 1] id(x) = 46390664 after func(), global! x = [1, 2, 3] id(x) = 46339976
x = x + [1],是新建了一個對象,id(x) = 46390664
利用id(x),查看下x += [1]對象是怎么變化的吧: x = [1,2,3] print "before func(), global! x = ",x,"id(x) = ",id(x) def func(x): print "in func(), local! original x = ",x,"id(x) = ",id(x) x += [1] print "in func(), local! now x = ",x,"id(x) = ",id(x) func(x) print "after func(), global! x = ",x,"id(x) = ",id(x) 結果: before func(), global! x = [1, 2, 3] id(x) = 46536584 in func(), local! original x = [1, 2, 3] id(x) = 46536584 in func(), local! now x = [1, 2, 3, 1] id(x) = 46536584 after func(), global! x = [1, 2, 3, 1] id(x) = 46536584
id(x)全程一樣,x += [1],python直接就在原對象上操作
參考:
1、http://blog.csdn.net/emaste_r/article/details/47395055