Mysql下SELECT的結果集作為UPDATE的WHERE條件時的SQL語法

UPDATE `WarningSendMail` AS alias_1 INNER JOIN (SELECT * FROM `WarningSendMail` WHERE flag=1 AND topic_id LIKE "%2267%") AS alias_2 SET alias_1.topic_id = REPLACE(alias_1.topic_id,'|2267','') WHERE alias_1.id = alias_2.id



update WarningSendMail set topic_id= REPLACE(topic_id,'|2267','') WHERE id IN ( SELECT id FROM WarningSendMail WHERE flag=1 AND topic_id LIKE "%2267%" );