1、使用not in,容易理解,效率低
select distinct A.ID from A where A.ID not in (select ID from B)
2、使用left join...on... ,B.ID isnull表示左連接之后在B.ID字段為null的記錄
select A.ID from A left join B on A.ID=B.ID where B.ID is null
3、邏輯相對復雜,但是速度最快
select * from B where (select count(1) as num from A where A.ID = B.ID) = 0
參考:
http://blog.csdn.net/u012732259/article/details/42215119/(以上內容轉自此篇文章)