1、distinct
select count(distinct CName) from Course select count(CName) from (select distinct CName from Course) as temp
2、group by
select count(1) from Course group by CName
1、distinct
select count(distinct CName) from Course select count(CName) from (select distinct CName from Course) as temp
2、group by
select count(1) from Course group by CName
本站轉載的文章為個人學習借鑒使用,本站對版權不負任何法律責任。如果侵犯了您的隱私權益,請聯系本站郵箱yoyou2525@163.com刪除。