js判斷幾個字符串是否有重復

   var Rank1 = $('.rank').children('*:nth-child(1)').find('.rankLis span').text();
   var Rank2 = $('.rank').children('*:nth-child(2)').find('.rankLis span').text();
   var Rank3 = $('.rank').children('*:nth-child(3)').find('.rankLis span').text();
   var Rank4 = $('.rank').children('*:nth-child(4)').find('.rankLis span').text();
        console.log(Rank1)
        console.log(Rank2)
        console.log(Rank3)
        console.log(Rank4)
         
        //判斷幾個字符串是否有重復
        var ary = new Array(Rank1,Rank2,Rank3,Rank4);
        var nary=ary.sort();
        for(var i=0;i<ary.length;i++){
            if (nary[i]==nary[i+1]){
            console.log("數組重復內容："+nary[i]);
        }

參考鏈接:https://zhidao.baidu.com/question/692544747795585524.html