python多行匹配
r = re.compile("需要的正則表達式", re.M)
匹配到需要的字符,可以獲取紅括號內的數字
r = re.compile("r
([0-9]{5,}
)")
舉個例子: 需要獲取20462和24729連個數字
import re
data = """
r24062 line1
hello word !!!!
r24729 line2
revision:24181
"""
r = re.compile("^r([0-9]{5,})", re.M)
nums = r.findall(data)
print nums
---------------------
output:["24062", "24729"]
如果你要多行匹配,那么加上re.S和re.M標志
re.S:.將會匹配換行符,默認.逗號不會匹配換行符
>>> re.findall(r"a(\d+)b.+a(\d+)b","a23b\na34b")
[]
>>> re.findall(r"a(\d+)b.+a(\d+)b","a23b\na34b",re.S)
[('23','34')]
>>>
[]
>>> re.findall(r"a(\d+)b.+a(\d+)b","a23b\na34b",re.S)
[('23','34')]
>>>
re.M:^$標志將會匹配每一行,默認^只會匹配符合正則的第一行;默認$只會匹配符合正則的末行
>>> re.findall(r"^a(\d+)b","a23b\na34b")
['23']
>>> re.findall(r"^a(\d+)b","a23b\na34b",re.M)
['23','34']
['23']
>>> re.findall(r"^a(\d+)b","a23b\na34b",re.M)
['23','34']
但是,如果沒有^標志,
>>> re.findall(r"a(\d+)b","a23b\na34b")
['23','43']
['23','43']
可見,是無需re.M