如何計算1+……+100中偶數和?
1. 把奇數去掉,通過if,判斷累加數除以2的余數,是否為1,判斷是否是奇數
2. 通過continue 跳過對奇數的累加
#!/usr/bin/python3
def sum_go(sum_to):
'''計算1+……+100中偶數和'''
count = 0
sum_all = 0
while count <= sum_to:
count += 1
if count % 2 == 1:
continue
else:
print(count)
sum_all += count
return sum_all
if __name__ =='__main__':
result = sum_go(sum_to=100)
print('結果是:%s' % result)
