如何計算1+……+100中偶數和?
1. 把奇數去掉,通過if,判斷累加數除以2的余數,是否為1,判斷是否是奇數
2. 通過continue 跳過對奇數的累加
#!/usr/bin/python3 def sum_go(sum_to): '''計算1+……+100中偶數和''' count = 0 sum_all = 0 while count <= sum_to: count += 1 if count % 2 == 1: continue else: print(count) sum_all += count return sum_all if __name__ =='__main__': result = sum_go(sum_to=100) print('結果是:%s' % result)