含有對象的List集合實現字母數字混合排序

List<PageData>    varList =  [{BOMCode=10A, mantotal=4}, {BOMCode=10B, mantotal=1}, {BOMCode=11A, mantotal=1}, {BOMCode=11B, mantotal=1}, {BOMCode=12A, mantotal=1}, {BOMCode=1A, mantotal=9}, {BOMCode=2A, mantotal=168}, {BOMCode=2B, mantotal=57}, {BOMCode=3A, mantotal=440}, {BOMCode=3B, mantotal=363}, {BOMCode=4A, mantotal=317}, {BOMCode=4B, mantotal=612}, {BOMCode=5A, mantotal=175}, {BOMCode=5B, mantotal=188}, {BOMCode=6A, mantotal=99}, {BOMCode=6B, mantotal=132}, {BOMCode=7A, mantotal=48}, {BOMCode=7B, mantotal=58}, {BOMCode=8A, mantotal=22}, {BOMCode=8B, mantotal=10}, {BOMCode=9A, mantotal=7}, {BOMCode=9B, mantotal=3}]

現在要對集合對象里面的BOMCode做排序，返回一個排序后的varList：

Collections.sort(varList, new Comparator<PageData>(){                
            /*  
             * int compare(PageData pd1, PageData pd2) 返回一個基本類型的整型，  
             * 返回負數表示：pd1 小於pd2，  
             * 返回0 表示：pd1和pd2相等，  
             * 返回正數表示：pd1大於pd2。  
             */  
            @Override
            public int compare(PageData pd1, PageData pd2) {
                int number1;
                int number2;
                int ascii1 = 0;
                int ascii2 = 0;
                String s1 = pd1.getString("BOMCode");
                String s2 = pd2.getString("BOMCode");
                // 獲取每個數字的最后一位，判斷是否為大寫字母（判斷其ASCII碼是否在65到90之間）
                if ((int) (s1.toCharArray()[s1.length() - 1]) >= 65
                        && (int) (s1.toCharArray()[s1.length() - 1]) <= 90) {
                    number1 = Integer.parseInt(s1.substring(0,
                            s1.length() - 1));
                    ascii1 = (int) (s1.toCharArray()[s1.length() - 1]);
                } else {
                    number1 = Integer.parseInt(s1);
                }
                if ((int) (s2.toCharArray()[s2.length() - 1]) >= 65
                        && (int) (s2.toCharArray()[s2.length() - 1]) <= 90) {
                    number2 = Integer.parseInt(s2.substring(0,
                            s2.length() - 1));
                    ascii2 = (int) (s2.toCharArray()[s2.length() - 1]);
                } else {
                    number2 = Integer.parseInt(s2);
                }
                // 從小到大排序
                if (number1 > number2) {
                    return 1;
                } else if (number1 == number2) {// 數值相等則判斷是否有字母以及字母的順序
                    // 如果兩個都有字母，則判斷順序
                    // 按ASCII碼從小到大排列（即從A到Z排列）
                    if (ascii1 < ascii2) {
                        return 1;
                    }
                } 
                return -1;
            }  
        });
        return varList;

最后返回的varList如下：

[{BOMCode=1A, mantotal=9}, {BOMCode=2B, mantotal=57}, {BOMCode=2A, mantotal=168}, {BOMCode=3B, mantotal=363}, {BOMCode=3A, mantotal=440}, {BOMCode=4B, mantotal=612}, {BOMCode=4A, mantotal=317}, {BOMCode=5B, mantotal=188}, {BOMCode=5A, mantotal=175}, {BOMCode=6B, mantotal=132}, {BOMCode=6A, mantotal=99}, {BOMCode=7B, mantotal=58}, {BOMCode=7A, mantotal=48}, {BOMCode=8B, mantotal=10}, {BOMCode=8A, mantotal=22}, {BOMCode=9B, mantotal=3}, {BOMCode=9A, mantotal=7}, {BOMCode=10B, mantotal=1}, {BOMCode=10A, mantotal=4}, {BOMCode=11B, mantotal=1}, {BOMCode=11A, mantotal=1}, {BOMCode=12A, mantotal=1}]