[ Python - 7 ] 簡單的省份查詢系統

主要是練習while 循環和 if 條件判斷的使用

#!_*_coding:utf-8_*_
# Author: hkey

def options(list):
    for i, v in enumerate(list):
        print(i + 1, v)
    choice = input('\33[34;1m請選擇:\33[0m')
    return choice

def city(list):
    while True:
        choice = options(list)
        if choice == str(len(list)):
            break

def start():
    while True:
        print('\33[32;1m歡迎查詢省份城市\33[0m'.center(30, '#'))
        choice = options(prov_list)
        if choice == '1':
            city(sx)
        elif choice == '2':
            city(shanxi)
        elif choice == '3':
            city(sh)
        if choice == '4':
            break

if __name__ == '__main__':
    prov_list = ['陝西省', '山西省', '上海市', '退出']
    sx = ['西安市', '安康市', '咸陽市', '返回']
    shanxi = ['太原市', '運城市', '返回']
    sh = ['上海市', '返回']
    start()

 另一個版本：

# -*- coding: utf-8 -*-
prov_list = ['陝西省', '浙江省', '退出']
sx_city_list = ['西安市', '咸陽市', '寶雞市', '返回']
zj_city_list = ['杭州市', '寧波市', '紹興市', '返回']

while True:
    for k, v in enumerate(prov_list):
        print(k+1, v)
    choice = input('\33[34;1m請選擇：\33[1m')
    if choice == '1':
        while True:
            for k, v in enumerate(sx_city_list):
                print(k+1, v)
            choice = input('\33[34;1m請選擇：\33[1m')
            if choice == str(len(sx_city_list)):
                break
    elif choice == '2':
        while True:
            for k, v in enumerate(zj_city_list):
                print(k+1, v)
            choice = input('\33[34;1m請選擇：\33[1m')
            if choice == str(len(zj_city_list)):
                break
    elif choice == '3':
        break
    else:
        print('輸入序號不存在，請重新輸入!')