jquery 獲取訪問當前頁面的開源設備信息


 1 <!DOCTYPE html>
 2 <html>
 3 <head>
 4     <title>測試js</title>
 5     <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
 6     <script src="jquery-1.8.3.min.js"></script>
 7     <style type="text/css">.content{color: red;font-size: 15px;}</style>
 8 </head>
 9 <body>
10     展示設備
11     <p class="content"></p>
12     <p class="agentsinfo"></p>
13 </body>
14 <script type="text/javascript">
15 var userAgentInfo = navigator.userAgent;
16 function IsAgent() { 
17     var Agents = ["Android", "iPhone","SymbianOS", "Windows Phone","iPad", "iPod", "Windows"];
18     var res = '';
19     for (var v = 0; v < Agents.length; v++) {
20         if (userAgentInfo.indexOf(Agents[v]) > 0) {
21             res = Agents[v];
22             break;
23         }
24     }
25     return res;
26 }
27 console.log(navigator.userAgent);
28 
29 console.log('這部設備是:'+IsAgent());
30 $('.agentsinfo').html('設備信息:'+userAgentInfo);
31 </script>
32 </html>


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