MySQL練習-主外鍵多表查詢


練習:

1.建立表關系:

請創建如下表,並創建相關約束

 

 1 USE db1;
 2 CREATE TABLE class(
 3     cid INT AUTO_INCREMENT PRIMARY KEY,
 4     caption VARCHAR(10)
 5 );
 6 CREATE TABLE teacher(
 7     tid INT AUTO_INCREMENT PRIMARY KEY,
 8     tname VARCHAR(10)
 9 );
10 CREATE TABLE course(
11     cid INT AUTO_INCREMENT PRIMARY KEY,
12     cname VARCHAR(10),
13     teach_id INT,
14     CONSTRAINT fk_course_teacher FOREIGN KEY(teach_id) REFERENCES teacher(tid)
15 );
16 CREATE TABLE student(
17     sid INT AUTO_INCREMENT PRIMARY KEY,
18     sname VARCHAR(10),
19     gender VARCHAR(10),
20     class_id INT,
21     CONSTRAINT fk_student_class FOREIGN KEY(class_id) REFERENCES class(cid)
22 );
23 CREATE TABLE score(
24     sid INT AUTO_INCREMENT PRIMARY KEY,
25     student_id INT,
26     course_id INT,
27     number INT,
28     CONSTRAINT fk_score_student FOREIGN KEY(student_id) REFERENCES student(sid),
29     CONSTRAINT fk_score_course FOREIGN KEY(course_id) REFERENCES course(cid)
30 );
創建表並建立表關系
 1 INSERT INTO class(caption) VALUES("三年二班");
 2 INSERT INTO class(caption) VALUES("一年三班");
 3 INSERT INTO class(caption) VALUES("三年一班");
 4 
 5 INSERT INTO teacher(tname) VALUES("波多");
 6 INSERT INTO teacher(tname) VALUES("蒼空");
 7 INSERT INTO teacher(tname) VALUES("飯島");
 8 
 9 INSERT INTO student(sname,gender,class_id) VALUES("鋼蛋","女",1);
10 INSERT INTO student(sname,gender,class_id) VALUES("鐵錘","女",1);
11 INSERT INTO student(sname,gender,class_id) VALUES("山炮","男",2);
12 
13 INSERT INTO course(cname,teach_id) VALUES("生物",1);
14 INSERT INTO course(cname,teach_id) VALUES("體育",1);
15 INSERT INTO course(cname,teach_id) VALUES("物理",2);
16 
17 INSERT INTO score(student_id,course_id,number) VALUES(1,1,60);
18 INSERT INTO score(student_id,course_id,number) VALUES(1,2,59);
19 INSERT INTO score(student_id,course_id,number) VALUES(2,2,100);
表數據
1 ALTER TABLE score ADD UNIQUE sco_que(student_id,course_id);
補充聯合唯一

2.操作練習:

1、自行創建測試數據

1 INSERT INTO student(sname,gender,class_id) VALUES("鋼鐵俠","男",4);
2 -- Cannot add or update a child row: a foreign key constraint fails (`db1`.`student`, CONSTRAINT `fk_student_class` FOREIGN KEY (`class_id`) REFERENCES `class` (`cid`))
測試失敗數據

2、查詢“生物”課程比“物理”課程成績高的所有學生的學號;

1 SELECT s1.student_id FROM (SELECT a.student_id,a.`number` FROM score a,course b 
2 WHERE a.`course_id` = b.`cid` AND b.`cname` ="生物") s1 , (SELECT a.student_id,a.`number` FROM score a,course b 
3 WHERE a.`course_id` = b.`cid` AND b.`cname`="體育") s2
4 WHERE s1.`student_id` = s2.student_id AND s1.number >s2.number
多表嵌套查詢

3、查詢平均成績大於60分的同學的學號和平均成績;

1 SELECT student_id,AVG(number)
2 FROM score 
3 GROUP BY student_id
4 HAVING AVG(number) > 60
HAVING用法

4、查詢所有同學的學號、姓名、選課數、總成績;

1 SELECT a.`sid`,a.`sname`,b.`cname`,c.`number`,c.`course_id`,a.`class_id` 
2 FROM student a,course b,score c
3 WHERE a.`sid` = c.`student_id` AND c.`course_id` = b.`cid`
多表查詢

5、查詢姓“李”的老師的個數;

1 SELECT count(*) as a from teacher where tname LIKE '李%'

6、查詢沒學過“葉平”老師課的同學的學號、姓名;

1 SELECT a.sid,a.sname FROM student a,teacher b,course c
2 WHERE a.class_id = c.cid and b.tid = c.teach_id AND b.tname != '葉平'
多表查詢

7、查詢學過“001”並且也學過編號“002”課程的同學的學號、姓名;

1 SELECT a.`student_id`,c.`sname` FROM score a , score b ,student c
2 WHERE a.`student_id`=b.`student_id` AND a.`course_id` ='1' 
3 AND b.`course_id`='2' AND c.`sid` = a.`student_id`
多表查詢

8、查詢學過“葉平”老師所教的所有課的同學的學號、姓名;

 1 SELECT c.`sid`,c.`sname` FROM student c 
 2 LEFT JOIN score d ON c.`sid` = d.`student_id`
 3 LEFT JOIN course b ON d.`course_id` = b.`cid`
 4 LEFT JOIN teacher a ON a.`tid` = b.`teach_id`
 5 WHERE a.`tname`='波多'
 6 GROUP BY c.`sname`
 7 HAVING COUNT(c.sname)
 8 <(SELECT COUNT(*) FROM teacher a 
 9 LEFT JOIN course b ON a.`tid` = b.`teach_id`
10 WHERE a.`tname`='波多')
亂七八糟一大堆

9、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名;

1 SELECT s1.student_id FROM (SELECT a.student_id,a.`number` FROM score a,course b 
2 WHERE a.`course_id` = b.`cid` AND b.`cid` ='2') s1 , (SELECT a.student_id,a.`number` FROM score a,course b 
3 WHERE a.`course_id` = b.`cid` AND b.`cid`='1') s2
4 WHERE s1.`student_id` = s2.student_id AND s1.number >s2.number
多表嵌套查詢

10、查詢有課程成績小於60分的同學的學號、姓名;

1 SELECT a.`sid`,a.`sname` FROM student a , score    b
2 WHERE a.sid = b.student_id AND number < 60

11、查詢沒有學全所有課的同學的學號、姓名;

1 SELECT a.`sid`,a.`sname` FROM student a 
2 LEFT JOIN score b ON  a.`sid` = b.`student_id`
3 GROUP BY a.`sid`
4 HAVING COUNT(b.`student_id`) < (SELECT COUNT(*) FROM course)
Having 子查詢

12、查詢至少有一門課與學號為“001”的同學所學相同的同學的學號和姓名;

1 SELECT a.`sid`,a.`sname` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
2 LEFT JOIN course c ON c.`cid` = b.`course_id`
3 WHERE c.`cid` IN (
4 SELECT cc.`cid` FROM student aa LEFT JOIN score bb ON aa.`sid` = bb.`student_id`
5 LEFT JOIN course cc ON cc.`cid` = bb.`course_id` WHERE aa.`sid`='1'
6 ) AND a.`sid` !='1'
又是亂七八糟一大堆

13、查詢至少學過學號為“001”同學所選課程中任意一門課的其他同學學號和姓名;

SELECT a.`sid`,a.`sname` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
LEFT JOIN course c ON c.`cid` = b.`course_id`
WHERE c.`cid` IN (
SELECT cc.`cid` FROM student aa LEFT JOIN score bb ON aa.`sid` = bb.`student_id`
LEFT JOIN course cc ON cc.`cid` = bb.`course_id` WHERE aa.`sid`='1'
) AND a.`sid` !='1'
完全一模一樣啊

14、查詢和“002”號的同學學習的課程完全相同的其他同學學號和姓名;

 1 SELECT a.`sid`,a.`sname` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
 2 LEFT JOIN course ac ON b.`course_id`=ac.`cid`
 3 WHERE
 4  ac.`cid` IN (SELECT c.`cid` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
 5 LEFT JOIN course c ON b.`course_id`=c.`cid` WHERE a.`sid`='2') 
 6 AND a.`sid` != '2' 
 7 GROUP BY a.`sid`,a.`sname`
 8 HAVING
 9 (SELECT COUNT(ac.`cid`) AS countCid FROM student aa LEFT JOIN score b ON aa.`sid` = b.`student_id`
10 LEFT JOIN course ac ON b.`course_id`=ac.`cid` WHERE aa.`sid`=a.`sid`)
11  = (SELECT COUNT(c.`cid`) AS cc FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
12 LEFT JOIN course c ON b.`course_id`=c.`cid` WHERE a.`sid`='2')
摳摳摳摳摳一下午,摳出來了

15、刪除學習“葉平”老師課的SC表記錄;

1 DELETE FROM score WHERE course_id IN (
2 SELECT a.`cid` FROM course a LEFT JOIN teacher b ON a.`teach_id`=b.`tid`
3 WHERE b.`tname`='葉平'
4 )
這個這么簡單?

16、向SC表中插入一些記錄,這些記錄要求符合以下條件:①沒有上過編號“002”課程的同學學號;②插入“002”號課程的平均成績;
17、按平均成績從低到高顯示所有學生的“語文”、“數學”、“英語”三門的課程成績,按如下形式顯示: 學生ID,語文,數學,英語,有效課程數,有效平均分;
18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分;
19、按各科平均成績從低到高和及格率的百分數從高到低順序;
20、課程平均分從高到低顯示(現實任課老師);
21、查詢各科成績前三名的記錄:(不考慮成績並列情況)
22、查詢每門課程被選修的學生數;
23、查詢出只選修了一門課程的全部學生的學號和姓名;
24、查詢男生、女生的人數;
25、查詢姓“張”的學生名單;
26、查詢同名同姓學生名單,並統計同名人數;
27、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列;
28、查詢平均成績大於85的所有學生的學號、姓名和平均成績;
29、查詢課程名稱為“數學”,且分數低於60的學生姓名和分數;
30、查詢課程編號為003且課程成績在80分以上的學生的學號和姓名;
31、求選了課程的學生人數
32、查詢選修“楊艷”老師所授課程的學生中,成績最高的學生姓名及其成績;
33、查詢各個課程及相應的選修人數;
34、查詢不同課程但成績相同的學生的學號、課程號、學生成績;


35、查詢每門課程成績最好的前兩名;

1 SELECT student_id FROM score 
2 ORDER BY number DESC LIMIT 2
這個肯定不對

36、檢索至少選修兩門課程的學生學號;

1 SELECT a.`sid` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
2 GROUP BY a.`sid`
3 HAVING COUNT(a.`sid`)>=2
完美~

37、查詢全部學生都選修的課程的課程號和課程名;

1 SELECT DISTINCT c.`cid`,c.`cname` FROM student a 
2 LEFT JOIN score b ON a.`sid` = b.`student_id`
3 LEFT JOIN course c ON b.`course_id`=c.`cid`
應該對了

38、查詢沒學過“葉平”老師講授的任一門課程的學生姓名;

1 SELECT a.`sname` FROM student a 
2 LEFT JOIN score b ON a.`sid` = b.`student_id`
3 LEFT JOIN course c ON c.`cid` = b.`course_id`
4 WHERE c.`cid` NOT IN (
5 SELECT cour.`cid` FROM teacher teac 
6 LEFT JOIN course cour ON teac.`tid`=cour.`teach_id`
7 WHERE teac.`tname` = '波多' 
8 )
差不多吧

39、查詢兩門以上不及格課程的同學的學號及其平均成績;

1 SELECT student_id,COUNT(sid) AS co,AVG(number)AS avgg  FROM score 
2 WHERE number < 60 
3 GROUP BY student_id
4 HAVING co >=2
so anyway

40、檢索“004”課程分數小於60,按分數降序排列的同學學號;

1 SELECT b.`sid`,b.`sname`,a.`number` FROM score a LEFT JOIN student b ON a.`student_id` = b.`sid`
2 WHERE a.`course_id` = '4' AND a.`number` < '60'
3 ORDER BY a.`number` DESC
恩不難

41、刪除“002”同學的“001”課程的成績;

1 DELETE FROM score WHERE student_id ='2' AND course_id = '1'

 


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