1、左連接:
var LeftJoin = from t1 in l1
join t2 in l2
on t1.ID equals t2.ID into Joinedt12
from t3 in Joinedt12.DefaultIfEmpty()
select new
{
Name = t1.Name,
Age=t2.Age
};
2、右連接:
var RightJoin = from t2 in l2
join t1in l1
on t2.ID equals t1.ID into joint12
from t3 in joint12.DefaultIfEmpty()
select new
{
Name = t1.Name,
Age=t2.Age
};
3、內連接:
var query = from t1 in l1
join t2 in l2
on t1.ID equals t2.ID
select new t3
{
USER_ID = t1.USER_ID,
USER_NAME = t1.USER_NAME,
USER_PASSWORD = t1.USER_PASSWORD,
};
注:上例中使用了DefaultIfEmpty操作符,它能夠為實序列提供一個默認的元素。DefaultIfEmpty使用了泛型中的default關鍵字。default關鍵字對於引用類型將返回null,而對於值類型則返回0。對於結構體類型,則會根據其成員類型將它們相應地初始化為null(引用類型)或0(值類型)
我們可以不使用default關鍵字,但在要DefaultIfEmpty中給定當空時的默認對象值。
Lamda表達式實現Left join
public class AnalysisPlayer
{
/// <summary>
/// 玩家名稱
/// </summary>
public string PlayerName { get; set; }
/// <summary>
/// 玩家賬號
/// </summary>
public string Account { get; set; }
/// <summary>
/// 注冊時間
/// </summary>
public DateTime RegTime { get; set; }
/// <summary>
/// 充值總數
/// </summary>
public int Points { get; set; }
}
------解決方案--------------------
var query = User.GroupJoin(Charge, u => u.Account, c => c.Account, (u, c) => new { u, c })
.Select(data => new AnalysisPlayer { Account = data.u.Account, PlayerName = data.u.Name,
RegTime = data.u.CreateTime ?? DateTime.Now, Points =data.c==null?0:data.c.Points });
