有時候需要在前台自定義對象,然后把對象封裝在list中,在傳送到后台,這樣的思想也比較合理
1. 前台代碼
$scope.saveScore = function () {
$scope.userScoreList = new Array();//自定義數組
angular.forEach ($scope.records, function (record, index) {
if (record.score != null) {
$scope.userScoreModel = {'userAnswerId': null,'score': null};//自定義對象結構
$scope.userScoreModel.userAnswerId = record.userAnswerId;//賦值
$scope.userScoreModel.score = record.score;
$scope.userScoreList.push($scope.userScoreModel);//把對象封裝在集合中
debugger;
}
});
if ($scope.userScoreList != null && $scope.userScoreList.length > 0) {
var fd = new FormData();// 使用angularJS的FormData封裝要傳送的數據
var userScoreRecords = angular.toJson($scope.userScoreList);//把對象(集合)轉換為json串
fd.append('userScoreRecords', userScoreRecords);//參數放入formData中
debugger;//使用 debugger模式查看傳值情況
$http.post('/reviewProcess/save', fd, { //使用post方法 傳送formdata對象
transformRequest: angular.identity, //使用angular傳參認證
headers: {
'Content-Type': undefined //設置請求頭
}
})
.success(function (data){
toastr.success("success");
})
.error(function (data) {
toastr.success("failed");
});
}
};
2. 后台接收
@ResponseBody
@RequestMapping(value = "/reviewProcess/save", method = RequestMethod.POST)
public void saveUserScore (@RequestParam("userScoreRecords") String userScoreRecords) { //使用requestparam接收前台傳送的json串
System.out.println(userScoreRecords);
ObjectMapper mapper = new ObjectMapper(); // 使用fastJson的ObjectMapper反序列化json串為對象
UserScoreModel record = null;
try {
JSONArray jsonArray = new JSONArray (userScoreRecords); //在后台把json串轉換為json數組
for (int i =0; i < jsonArray.length(); i++) {
record = mapper.readValue(jsonArray.getJSONObject(i).toString(), UserScoreModel.class); //獲取json數組的json對象並且反序列化為對應的對象
System.out.println(record); // 得到對象后后台即可操作
}
} catch (Exception e) {
logger.error(e.getMessage(), e);
}
}
