解析嵌套json字符串，一個json字符串中嵌套另一個json字符串

我現在有一個字符串是這樣：

{
     "msg": {
     "resCode": "0000",
     "attrName": "sensorData",

　　 "result": {
     　　"food1": 0,
     　　"water": 0,
     　　"food2": 106,
     　　"humidity": "152.42",
     　　"temprature": "103.65"
     }
     }
 }

我要獲取的是嵌套在msg里的result中的所有數據。

 

先用msg和result分別創建bean類，把Result作為msg的其中一個變量

public class SensorBean implements Serializable {

   private Result result;

    private int resCode;

    private String attrName;10 
    public Result getResult() {
        return result;
    }

    public void setResult(Result result) {
        this.result = result;
    }

    public int getResCode() {
        return resCode;
    }

    public void setResCode(int resCode) {
        this.resCode = resCode;
    }

    public String getAttrName() {
        return attrName;
    }

    public void setAttrName(String attrName) {
        this.attrName = attrName;
    }42 
    @Override
    public String toString() {
        return "Msg{" +
                "result=" + result.toString() +
                ", resCode=" + resCode +
                ", attrName='" + attrName + '\'' +
                '}';
    }

}

兩個類都繼承序列化

public class Result implements Serializable{

    /**
     * food1 : 0
     * water : 0
     * food2 : 106
     * humidity : 152.42
     * temprature : 103.65
     */

    private int food1;
    private int water;
    private int food2;
    private String humidity;
    private String temprature;

    public int getFood1() {
        return food1;
    }

    public void setFood1(int food1) {
        this.food1 = food1;
    }

    public int getWater() {
        return water;
    }

    public void setWater(int water) {
        this.water = water;
    }

    public String getTemprature() {
        return temprature;
    }

    public void setTemprature(String temprature) {
        this.temprature = temprature;
    }

    @Override
    public String toString() {
        return "Result{" +
                "food1=" + food1 +
                ", water='" + water +
                ", temprature=" + temprature+ '\''+
                '}';
    }
}

然后在獲取到數據的地方進行Gson解析

Gson gson = new Gson();
SensorBean sensorBean = gson.fromJson(data.getString("msg"), SensorBean.class);
Result result = sensorBean.getResult();
L.d(TAG, "result.bean = " + result.toString());

這種方法應該是比較費事兒的，不過，沒毛病