//有一個參數的返回的是string類型的字符串,我想用int接收,提供給后面使用,需寫好轉換邏輯
static class StringDeserializer extends JsonDeserializer<Integer> { @Override public Integer deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException, JsonProcessingException { return (jp.getText() == null || "".equals(jp.getText())) ? 0 : 1; } }
在該字段上加注解
@JsonDeserialize(using = StringDeserializer.class)
private int errorCode;
如果是xml類型的數據(String轉money)
static class MoneyAdapter extends XmlAdapter<String, Money> {
/**
* {@inheritDoc}
*
* @see javax.xml.bind.annotation.adapters.XmlAdapter#unmarshal(java.lang.Object)
*/
@Override
public Money unmarshal(String v) throws Exception {
return new Money(v);
}
/**
* {@inheritDoc}
*
* @see javax.xml.bind.annotation.adapters.XmlAdapter#marshal(java.lang.Object)
*/
@Override
public String marshal(Money v) throws Exception {
return v.toString();
}
}
在相應字段加注解,就行了
@XmlJavaTypeAdapter(MoneyAdapter.class)
@XmlElement(name = "remain_value")
private Money remainValue;
