sql語句查詢出表里符合條件的第二條記錄的方法

創建用到的表的SQL

CREATE TABLE [dbo].[emp_pay](
    [employeeID] [int] NOT NULL,
    [base_pay] [money] NOT NULL,
    [commission] [decimal](2, 2) NOT NULL
) ON [PRIMARY]

生成的表，及表中的數據：

 

--方法一 select top 1 * from ( SELECT TOP 2 * FROM [dbo].[emp_pay] WHERE base_pay = 500 order by employeeID ASC) as a --注意：派生表后面一定要指定別名． order by a.employeeID DESC

 

--方法二 select IDENTITY(int,1,1) ID,* INTO #Temp from [dbo].[emp_pay] where base_pay = 500 select * from #Temp where ID =2 drop Table #Temp

 

--方法三 set rowcount 2 SELECT * into #t from [dbo].[emp_pay] where base_pay = 500 set rowcount 1 delete from #t select * from #t set rowcount 0 drop table #t