sql查找最后一個字符匹配

DECLARE @str AS VARCHAR(25)='123_234_567'
select substring(@str,1,LEN(@str)-CHARINDEX('_',reverse(@str)))

輸出 123_234

 

DECLARE @str AS VARCHAR(25)='123_234_567'
select reverse(substring(reverse(@str),1,charindex('_',reverse(@str)) - 1))

 

輸出567