來源:https://segmentfault.com/q/1010000002581747
方法一:直接遍歷 速度快
for key in _dict: pass
方法二:iterkeys() 速度快
for _ in testDict.iterkeys(): pass
方法三:keys() 速度慢 因為keys()須要形成一個列表,構建一個列表對於一個大的dict開銷是很大的。
for _ in testDict.keys(): pass
時間對比:
import timeit DICT_SIZE = 100*10000 testDict = dict() for i in range(DICT_SIZE): testDict[i] = i # 構建大小為100W的字典 assert len(testDict) == DICT_SIZE def test1(): for _ in testDict.keys(): pass def test2(): for _ in testDict: pass def test3(): for _ in testDict.iterkeys(): pass # 分別測試2K次 print timeit.timeit("test1()", setup="from __main__ import test1", number=2000) print timeit.timeit("test2()", setup="from __main__ import test2", number=2000) print timeit.timeit("test3()", setup="from __main__ import test3", number=2000)
輸出
54.1994677764
30.2660675759
31.3075812315
是windows + python 2.7的結果