方法一
<script type="text/javascript"> function browserRedirect() { var sUserAgent = navigator.userAgent.toLowerCase(); var bIsIpad = sUserAgent.match(/ipad/i) == "ipad"; var bIsIphoneOs = sUserAgent.match(/iphone os/i) == "iphone os"; var bIsMidp = sUserAgent.match(/midp/i) == "midp"; var bIsUc7 = sUserAgent.match(/rv:1.2.3.4/i) == "rv:1.2.3.4"; var bIsUc = sUserAgent.match(/ucweb/i) == "ucweb"; var bIsAndroid = sUserAgent.match(/android/i) == "android"; var bIsCE = sUserAgent.match(/windows ce/i) == "windows ce"; var bIsWM = sUserAgent.match(/windows mobile/i) == "windows mobile"; if (bIsIpad || bIsIphoneOs || bIsMidp || bIsUc7 || bIsUc || bIsAndroid || bIsCE || bIsWM) { document.writeln("phone"); } else { document.writeln("pc"); } } browserRedirect(); </script>
方法二
<script> var url = location.search; url = url.substr(1); var bs={ versions:function(){ var u = navigator.userAgent, app = navigator.appVersion; return {//移動終端瀏覽器版本信息 trident: u.indexOf('Trident') > -1, //IE內核 presto: u.indexOf('Presto') > -1, //opera內核 webKit: u.indexOf('AppleWebKit') > -1, //蘋果、谷歌內核 gecko: u.indexOf('Gecko') > -1 && u.indexOf('KHTML') == -1, //火狐內核 mobile: !!u.match(/AppleWebKit.*Mobile.*/)||!!u.match(/AppleWebKit/), //是否為移動終端 ios: !!u.match(/\(i[^;]+;( U;)? CPU.+Mac OS X/), //ios終端 android: u.indexOf('Android') > -1 || u.indexOf('Linux') > -1, //android終端或者uc瀏覽器 iPhone: u.indexOf('iPhone') > -1, //是否為iPhone或者QQHD瀏覽器 iPad: u.indexOf('iPad') > -1 //是否iPad }; }(), language:(navigator.browserLanguage || navigator.language).toLowerCase() } if(bs.versions.mobile && url!='mobile'){ if(bs.versions.android||bs.versions.iPhone||bs.versions.iPad||bs.versions.ios){ window.location.href="跳轉的手機地址"; }else{
window.location.href="跳轉的pc地址";
}
}
</script>
兩者都是一樣的原理,利用javascript中navigator對象下的userAgent屬性來做判斷只是兩者的返回一個是indexOf一個是match。
一般情況下我們還會有另外一個需求就是電腦當前地址跳轉到手機對應地址,比如www.baidu.com/news對應的是m.baidu.com/news這個時候用截取替換掉主域名即可。
var current_url = window.location.href;//獲取當前連接 //str2是被替換的鏈接str3替換后的鏈接 function replaceAll(current_url ,str2,str3){ var k; var tmp = str1.split(str2); k=tmp[0]; for(i=1;i<tmp.length;i++){ k+=str3+tmp[i]; } return k; }