例一:
SELECT num from user
1、使用group_concat函數得到列轉行
select group_concat(num) from user
2、使用SUBSTRING_INDEX和CROSS JOIN將列里面的的數字都拆分出來,把一行變成一列
方法一:建配置表(網上查詢的方法):
CREATE TABLE digits (digit INT(1)); INSERT INTO digits VALUES (0), (1), (2), (3), (4), (5), (6), (7), (8), (9); CREATE TABLE sequence (seq INT(3)); INSERT INTO sequence ( SELECT D1.digit + D2.digit * 10 FROM digits D1 CROSS JOIN digits D2 );
配置表sequence的結果為0-99的一列數字:
SQL:
SELECT SUBSTRING_INDEX( SUBSTRING_INDEX(num, ',', seq), ',' ,- 1 ) num FROM sequence CROSS JOIN user WHERE seq BETWEEN 1 AND ( SELECT 1 + LENGTH(num) - LENGTH( REPLACE (num, ',', '') ) )
方法二:將sequence替換為SELECT @rownum:=@rownum+1 AS seq FROM (SELECT @rownum:=0) r, user LIMIT 0,100) ,其中user為表名,這張表需要大於100條。(自己不想建表,圖省事)
SELECT SUBSTRING_INDEX( SUBSTRING_INDEX(num, ',', seq), ',' ,- 1 ) num FROM (SELECT @rownum:=@rownum+1 AS seq FROM (SELECT @rownum:=0) r, user LIMIT 0,100) b CROSS JOIN user WHERE seq BETWEEN 1 AND ( SELECT 1 + LENGTH(num) - LENGTH(REPLACE(num, ',', '')))
兩種方法結果均為:
例二:
將這樣的數據拆分出來,變成如下:
還是使用上述sql,只需添加一列即可。(標記紅色為新添加)
SELECT ID,SUBSTRING_INDEX( SUBSTRING_INDEX(num, ',', seq), ',' ,- 1 ) num FROM (SELECT @rownum:=@rownum+1 AS seq FROM (SELECT @rownum:=0) r, user LIMIT 0,100) b CROSS JOIN user WHERE seq BETWEEN 1 AND ( SELECT 1 + LENGTH(num) - LENGTH(REPLACE(num, ',', '')))
4、補充
1) 本篇文章中,user為表名,num為字段,自行替換就好。
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